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3 years ago

Once you have carried out your experiment and have some results, you should

Physics

1 answer:

katrin [286]3 years ago

4 0

Answer:

I think the answer is D

Explanation:

not sure

but if its correct can i get brainliest??

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Cuál es el método que utiliza el factor de la gravedad y la difusión de un líquido sobre un sólido para separar las partes de un

Airida [17]

Answer:

chromatography

Explanation:

Chromatography is one of the powerful technique that is used to separate the mixed components of liquid or the gas mixtures.

In this technique the separation of the mixture by passing the mixture in some solution or some suspension through the medium where the components are made to move at some different rates.

The basic idea in this experiment is that the mixture sample is in mobile phase and it is forced either by pumping or by gravity or by capillary action through the stationary phase to separate the mixture.

4 0

3 years ago

How does sound travel?

Doss [256]

Answer:

Sound vibrations travel in a wave pattern, and we call these vibrations sound waves. Sound waves move by vibrating objects and these objects vibrate other surrounding objects, carrying the sound along. ... Sound can move through the air, water, or solids, as long as there are particles to bounce off of.

Explanation:

8 0

3 years ago

Read 2 more answers

HELP ME DO THIS QUESTION PLEASE

raketka [301]

Answer:

i dont know

Explanation:

but what you can do is ask you mom or dad to get you a tutor to help you

7 0

3 years ago

An insect 1.1 mm tall is placed 1.0 mm beyond the focal point of the objective lens of a compound microscope. The objective lens

Pavlova-9 [17]

Answer:

Explanation:

For image formation in objective lens

object distance u = 14 +1 = 15 mm

focal length f = 14 mm .

image distance v = ?

lens formula

$\frac{1}{v} -\frac{1}{u} =\frac{1}{f}$

Putting the values

$\frac{1}{v} +\frac{1}{15} =\frac{1}{14}$

v = 210 mm .

B )

magnification = v / u

= 210 / 15

= 14

size of image = 14 x 1.1 mm

= 15.4 mm

= 15 mm approx

C )

For final image to be at infinity , image produced by objective lens must fall at the focal point of eye piece . so objective lens's distance from the image formed by objective must be equal to focal length of eye piece that is 21 mm .

21 mm is the answer .

D )

overall magnification =

$\frac{210}{15} \times \frac{D}{f_e}$

D = 25 cm , f_e = focal length of eye piece

= 14 x 250 / 21

= 166.67

= 170 ( in two significant figures )

7 0

3 years ago

PLEASE HELP I HAVE FINALSSS

vitfil [10]

Answer: 26.67 m/s

Explanation:

Given

Length traveled by the ball $s=40\ m$

Time taken to reach the goal post is $t=3\ s$

Initial velocity $u=0\ m/s$

Using the second equation of motion

$\Rightarrow s=ut+\frac{1}{2}at^2\\\Rightarrow 40=0+\frac{1}{2}a(3)^2\\\Rightarrow a=\frac{80}{9}\ m/s^2\\$

Now using

$\Rightarrow v^2-u^2=2as\\\\\Rightarrow v^2-0=2\times \frac{80}{9}\times 40\\\\\Rightarrow v=\sqrt{\dfrac{80\times 80}{9}}=\dfrac{80}{3}\\\Rightarrow v=26.67\ m/s$

The velocity of ball will be 26.67 m/s

8 0

3 years ago