5x(x-3) = (x-2)(5x - 1) - 5
5x^2 - 15x = 5x^2 - x - 10x + 2 - 5
5x^2 - 15x = 5x^2 - 11x - 3
5x^2 - 11x - 3 - 5x^2 + 15x = 0
4x - 3 = 0
4x = 3
x = 3/4 or 0.75
He first two are relatively easy. f(x-2) shifts it sideways (2 to the right in this case) f(x) -2 shifts it straight down (by 2)
f(2x) means replace x with 2x in the original 4(2x + 1)^2 − 3 if you factor out the 2 from the square root you get 4*sqr(2) ( x + ½)^2 - 3 which is now in the form a ( x -h)^2 + k the vertex is now at (-½, -3) (it used to be at (-1,-3) the "a" has gotten bigger, which makes the parabola "skinnier" (it goes up faster)
2•f(x) becomes 2*( 4(x + 1)2 − 3 ) = 8 (x+1)^2 -6 where is the vertex now? is this parabola fatter or skinnier than the original f(x) ?
<h3>
Answer: 1</h3>
========================================================
Explanation:
Pick any two points you want from the blue line. I'll pick (0,1) and (1,2)
Apply the slope formula to those points
m = (y2-y1)/(x2-x1)
m = (2-1)/(1-0)
m = 1/1
m = 1
The slope is 1.
Notice how if we're at (0,1), then we move up 1 and over to the right 1 to arrive at (1,2).
slope = rise/run = 1/1
rise = 1, run = 1
Answer:i dont know
Step-by-step explanation:
