Answer is: A) The shape.
Name of this organic chemical compound is cyclohexane.
Cyclohexane is cycloalkane (the monocyclic saturated hydrocarbons).
Cyclohexane has single covalent bond and carbons have sp3 hybridization as other alkanes (for example propane).
Propane is alkane, organic compound. Carbons in propane have sp3 hybridization (carbon’s 2s and three 2p orbitals combine into four identical sp3 orbitals). Orbitals in sp3 hybridization have a tetrahedral arrangement and form single (sigma) bonds.
Answer:
2.50 g of AlCl3
Explanation:
Goodness, stoichiometry...
So, what we need to find first is the amount of grams of AlCl3. To do this we look at the formula of molarity.
M = mols/L of solvent
So we know two parts of this formula. We have the Molarity (0.150) and the mL (125).
Now, we can't forget that we must convert 125 mL into liters so we have 0.125 L ( I forgot and had to do the entire problem again...)
So if we do the backwards equation we get:
0.150 = x/0.125
If we do math (fun ikr) we get 18.75 mols of the solution.
Now, we have to plug this wonderful number into stoichiometry
<u>0.01875 mols | 133.5 g</u>
<u>| 1 mol AgCl3</u>
If you are unfamiliar with what I'm doing, I'm basically going to multiply 0.01875*133.5 then divide that whole thing by 1.
So, I got 2.503125 g AlCl3
If your teacher is a stickler for significant figures there are 3 sig figs for this problem so your final answer should be
2.50 g of AlCl3
Hope you have a great day and fun with chemistry!!!!
Answer:
Condensing (I think is what you are looking for)
Explanation:
Boiling is liquid -> gas
Condensing is gas -> liquid
1) Balanced chemical equation
8H2S +4O2 ---> S8 + 8H2O
2) Molar ratios
8 mol H2S : 4 mol O2 : 1 mol S8
3) Convert 50.0 grams of H2S into moles
moles = mass in grams / molar mass
molar mass H2S = 2*1g/mol + 32.1 g/mol = 34.1 g/mol
moles = 50.0 g / 34.1 g/mol = 1.466 moles H2S
4) Convert 60.0 g of O2 into moles
molar mass O2 = 2*16g/mol = 32.0g/mol
moles = 60.0g / 32.0 g = 1.875 moles O2
5) State limiting reagent
Theoretical ratio: 8 mol H2S / 4 mol O2 = 8/4 = 2/1 = 2
Actual ratio 1.466 mol H2S / 1.875 mol O2 < 2
=> H2S is the limiting reagent (it is consumed completely whilce some O2 remains unreacted).
6) Determine the moles of S8 produced from 1.466 moles H2S
1 mol S8 / 8 mol H2S * 1.466 mol H2S = 0.18325 mol S8
7) Convert 0.18325 mol S8 to mass
mass = number of moles * molar mass
molar mass S8 = 8 mol * 32.1g/mol = 256.8 g/mol
mass = 0.18325 mol * 256.8 g/mol = 47.1 grams
Answer: 47.1 g