The condensation point of water is the same as its boiling point. This means that it is 100°C (212°F). Hope that helps!
<span>a) Lead(IV) Carbonate
b) </span><span>327.16
</span><span>
207.2 g + (12.01g + (15.99 x 3) ) x2 = </span><span>327.16 g</span>
Answer:
The answer to your question is 3.65 g of HCl
Explanation:
Data
volume = 1 l
[HCl] = 0.1 M
moles of HCl = ?
Process
1.- Calculate the number of moles
Molarity = moles / volume
-Solve for moles
moles = Molarity x volume
-Substitution
moles = 0.1 x 1
-Result
moles = 0.1 moles
2.- Convert moles to grams
-Calculate the molar mass of HCl
HCl = 1 + 35.5 = 36.5 g
-Convert
36.5 g of HCl ------------------- 1 mol
x ------------------- 0.1 moles
x = (0.1 x 36.5) / 1
-Result
x = 3.65 g
-How to prepare the solution
Once I have weighed the mass of HCl, I place it in a volumetric flask and pour enough water till 1 l.