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Aneli [31]
3 years ago
8

Describe the quantum model of an atom in terms of energy levels, sublevels, and orbitals. (Any atom is acceptable)

Chemistry
1 answer:
irakobra [83]3 years ago
5 0
<span>Quantum mechanic model is based on mathematics. As per this theory the exact position and momentum of electron is impossible to understand. It uses complex shapes of orbitals called electron clouds. n describes the energy of an electron. Larger the value of n larger the distance of electron from the nucleus and larger the orbital. l describles the shape of orbital. Orbitals having same of value of n and different values for l are called subshells.</span>
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The following reaction occurs in aqueous solution: NH4 + (aq) + NO2 - → N2 (g) + 2H2O (l) The data below is obtained at 25°C.
GREYUIT [131]

Answer: The order with respect to NH_4^+ is 1.

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

NH_4^++NO_2^-\rightarrow N_2+2H_2O

Rate=k[NH_4^+]^x[NO_2^-]^y

k= rate constant

x = order with respect to NH_4^+

y = order with respect to ANO_2^-

n = x+y = Total order

From trial 1: 3.2\times 10^{-3}=k[0.0100]^x[0.200]^y    (1)

From trial 2: 6.4\times 10^{-3}=k[0.0200]^x[0.200]^y    (2)

Dividing 2 by 1 :\frac{6.4\times 10^{-3}}{3.2\times 10^{-3}}=\frac{k[0.0100]^x[0.2000]^y}{k[0.0200]^x[0.200]^y}

2=2^x,2^1=2^x therefore x=  1

Thus order with respect to NH_4^+ is 1.

8 0
3 years ago
What is the percent composition of dinotrogen pentoxide? With work shown please
iris [78.8K]

Answer:

%N = 25.94%

%O = 74.06%

Explanation:

Step 1: Calculate the mass of nitrogen in 1 mole of N₂O₅

We will multiply the molar mass of N by the number of N atoms in the formula of N₂O₅.

m(N): 2 × 14.01 g = 28.02 g

Step 2: Calculate the mass of oxygen in 1 mole of N₂O₅

We will multiply the molar mass of O by the number of O atoms in the formula of N₂O₅.

m(O): 5 × 16.00 g = 80.00 g

Step 3: Calculate the mass of 1 mole of N₂O₅

We will sum the masses of N and O.

m(N₂O₅) = m(N) + m(O) = 28.02 g + 80.00 g = 108.02 g

Step 4: Calculate the percent composition  of N₂O₅

We will use the following expression.

%Element = m(Element)/m(Compound) × 100%

%N = m(N)/m(N₂O₅) × 100% = 28.02 g/108.02 g × 100% = 25.94%

%O = m(O)/m(N₂O₅) × 100% = 80.00 g/108.02 g × 100% = 74.06%

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