Answer: 5.1 gram
Explanation:
To calculate the moles :
According to stoichiometry :
1 mole of require = 1 mole of
Thus 0.41 moles of will require= of
Thus is the limiting reagent as it limits the formation of product and is the excess reagent.
Moles of HCl left = (0.55-0.41) = 0.14
Mass of left =
Thus 5.1 g of hydrochloric acid could be left over by the chemical reaction.
This uses the concept of freezing point depression. When faced with this issue, we use the following equation:
ΔT = i·Kf·m
which translates in english to:
Change in freezing point = vant hoff factor * molal freezing point depression constant * molality of solution
Because the freezing point depression is a colligative property, it does not depend on the identity of the molecules, just the number of them.
Now, we know that molality will be constant, and Kf will be constant, so our only unknown is "i", or the van't hoff factor.
The van't hoff factor is the number of atoms that dissociate from each individual molecule. The higher the van't hoff factor, the more depressed the freezing point will be.
NaCl will dissociate into Na+ and Cl-, so it has i = 2
CaCl2 will dissociate into Ca2+ and 2 Cl-, so it has i = 3
AlBr3 will dissociate into Al3+ and 3 Br-, so it has i = 4
Therefore, AlBr3 will lower the freezing point of water the most.
The anwser is B if that helps
Solute is what gets dissovled, in this case the salt, and the solVENT is whatever a material is dissolved into, in this case the water.