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Lapatulllka [165]
2 years ago
11

Please help me out with this math problem

Mathematics
2 answers:
mestny [16]2 years ago
8 0

Answer:

To know if the equation is true, you need to write it down on a piece of paper and see if you get the results.

Step-by-step explanation:

horrorfan [7]2 years ago
3 0

Because 1+1 = 2 and 3+5 = 8

That would be 2/8

Then you divide 2/8 in half

Half of 2 = 1

Half of 8 = 4

That’s how you get the answer, 1/4

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The graph shows the cost of ice cream. If a teacher wants to buy 20 cones, how much will it cost ?
Volgvan

Answer:

you cannot see the graph. So I cannot answer this question

Step-by-step explanation:

if you add the graph maybe I can help :D

6 0
3 years ago
Which term best describes the geometric figure?
nordsb [41]

Answer:

The geometric figure is a Segment

Step-by-step explanation:

A and B are points since they are shown by dots and a point usually marks a location.

In Geometry a line is straight  and  extends in both directions infinitely.

A line segment or simply segment is the part of a line that connects two points. A segment is the shortest distance between the two points and has a length.

5 0
3 years ago
Read 2 more answers
1. Suma a trei numere este 176. Al doilea numar este cu 28 mai mare decat al treilea, iar primul este egal cu diferenta acesteia
baherus [9]
Răspunsul corect va fi numărul 4. Supãrat dacã meu vorbind nu este cel mai bun, vorbesc limba engleza. Dacă ai nevoie de numere consecutive, sunt 99, 102 şi 103. 
7 0
2 years ago
Solve y ' ' + 4 y = 0 , y ( 0 ) = 2 , y ' ( 0 ) = 2 The resulting oscillation will have Amplitude: Period: If your solution is A
Vlad [161]

Answer:

y(x)=sin(2x)+2cos(2x)

Step-by-step explanation:

y''+4y=0

This is a homogeneous linear equation. So, assume a solution will be proportional to:

e^{\lambda x} \\\\for\hspace{3}some\hspace{3}constant\hspace{3}\lambda

Now, substitute y(x)=e^{\lambda x} into the differential equation:

\frac{d^2}{dx^2} (e^{\lambda x} ) +4e^{\lambda x} =0

Using the characteristic equation:

\lambda ^2 e^{\lambda x} + 4e^{\lambda x} =0

Factor out e^{\lambda x}

e^{\lambda x}(\lambda ^2 +4) =0

Where:

e^{\lambda x} \neq 0\\\\for\hspace{3}any\hspace{3}\lambda

Therefore the zeros must come from the polynomial:

\lambda^2+4 =0

Solving for \lambda:

\lambda =\pm2i

These roots give the next solutions:

y_1(x)=c_1 e^{2ix} \\\\and\\\\y_2(x)=c_2 e^{-2ix}

Where c_1 and c_2 are arbitrary constants. Now, the general solution is the sum of the previous solutions:

y(x)=c_1 e^{2ix} +c_2 e^{-2ix}

Using Euler's identity:

e^{\alpha +i\beta} =e^{\alpha} cos(\beta)+ie^{\alpha} sin(\beta)

y(x)=c_1 (cos(2x)+isin(2x))+c_2(cos(2x)-isin(2x))\\\\Regroup\\\\y(x)=(c_1+c_2)cos(2x) +i(c_1-c_2)sin(2x)\\

Redefine:

i(c_1-c_2)=c_1\\\\c_1+c_2=c_2

Since these are arbitrary constants

y(x)=c_1sin(2x)+c_2cos(2x)

Now, let's find its derivative in order to find c_1 and c_2

y'(x)=2c_1 cos(2x)-2c_2sin(2x)

Evaluating    y(0)=2 :

y(0)=2=c_1sin(0)+c_2cos(0)\\\\2=c_2

Evaluating     y'(0)=2 :

y'(0)=2=2c_1cos(0)-2c_2sin(0)\\\\2=2c_1\\\\c_1=1

Finally, the solution is given by:

y(x)=sin(2x)+2cos(2x)

5 0
3 years ago
8x5x2x4 whats dis answer
scoray [572]

Answer:

320

Step-by-step explanation:

5 0
3 years ago
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