Answer:
Number of dogs = 6
Number of burgers = 11
Step-by-step explanation:
Number of dogs = x
Number of burgers = 2x - 1
Cost of a dog = $ 1.50
Cost of 'x' dogs = 1.5x
Cost of a burger = $ 2
Cost of (2x - 1) burger = (2x -1) * 2 = 2x *2 - 1*2
= 4x - 2
Total amount collected = $ 31
1.5x + 4x - 2 = 31 {add 2 to both sides}
1.5x + 4x = 31 + 2
1.5x+ 4x = 33
5.5x = 33
x = 33/5.5
x = 6
Number of dogs = 6
Number of burgers = 2*6 - 1 = 12 - 1 = 11
<h3>(1136+1272)-(1138+{-1250})</h3><h3>=2408-(-112)</h3><h3>=2408+112</h3><h3>=2520</h3><h3>the answer is 2520</h3><h2 /><h2 /><h2>hope it helped :-)</h2>
Answer:
The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.
Step-by-step explanation:
Statement is incorrect. Correct form is presented below:
<em>The height </em>
<em> of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 90 feet per second is given by equation </em>
<em>, where </em>
<em> is time in seconds. After how many seconds will the ball be 84 feet above the ground. </em>
We equalize the kinematic formula to 84 feet and solve the resulting second-order polynomial by Quadratic Formula to determine the instants associated with such height:
![3+90\cdot t -16\cdot t^{2} = 84](https://tex.z-dn.net/?f=3%2B90%5Ccdot%20t%20-16%5Ccdot%20t%5E%7B2%7D%20%3D%2084)
(1)
By Quadratic Formula:
![t_{1,2} = \frac{90\pm \sqrt{(-90)^{2}-4\cdot (16)\cdot (81)}}{2\cdot (16)}](https://tex.z-dn.net/?f=t_%7B1%2C2%7D%20%3D%20%5Cfrac%7B90%5Cpm%20%5Csqrt%7B%28-90%29%5E%7B2%7D-4%5Ccdot%20%2816%29%5Ccdot%20%2881%29%7D%7D%7B2%5Ccdot%20%2816%29%7D)
,
The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.
<span>(2, 4) and (−8, 84)
see the graph</span>
I’m pretty sure the answer would be 8 if u cut 4 in half 4 times