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Rom4ik [11]
3 years ago
14

Which of the following measurements would be different for the same object on the earth and on the moon?

Chemistry
1 answer:
Tema [17]3 years ago
3 0
The gravity takes place in the objects
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The pka of hf is 3.2 determine the pkb of hf?
Julli [10]

Well, first we must remember that

pK_{a}+pK_{b}=14

This is because

K_{a}*K_{b}=10^{-14}

-log(K_{a}*K_{b})=-log(10^{-14})\\-logK_{a}+-logK_{b}=-log(10^{-14})\\pK_{a}+pK_{b}=14

So then

pK_{b}=14-pK_{a}=14-3.2=1.8

7 0
4 years ago
Read 2 more answers
A sample of gold (Au) has a mass of 35.12 g..
VMariaS [17]
A) Molar mass gold ( Au) = 196.96 g/mol

1 mole Au ----------- 196.96 g
? moles Au ---------- 35.12 g

35.12 x 1 / 196.96

= 0.178 moles of Au
_____________________________

b) 196.96 g --------------- 6.02x10²³ atoms
    35.12 g ---------------- ( atoms ? )

35.12 x ( 6.02x10²³) / 196.96

2.114x10²⁵ / 196.96

= 1.07x10²³ atoms
_____________________________________________

7 0
3 years ago
Read 2 more answers
Name two nineteenth century scientists—one who developed the laboratory burner
Viktor [21]

Answer:

1. Robert Bunsen hence being called the bunsen burner. 2. William Kirchhoff

Explanation:

4 0
4 years ago
The ideal value of the C-0-C angle at atom O2 is<br> degrees.
Tcecarenko [31]
Ethers have a tetrahedral geometry i.e. oxygen is sp
3
hybridized. The C−O−C bond angle is 110
o
. Because of the greater electronegativity of O than C, the C−O bonds are slightly polar & are inclined to each other at an angle of 110
o
, resulting in a net dipole moment. This bond angle greater than that of tetrahedral bond angle of 109
o
28
′
. This is due to the fact that internal repulsion by the hydrocarbon part is greater than the external repulsion of the lone pair of oxygen.
3 0
3 years ago
In the PhET simulation window, click the radio button labeled Mystery in the Blocks menu on the right-hand side of the screen. U
Yuliya22 [10]

Answer:

B, D, E, C, A

Explanation:

We have 5 blocks with their respective masses and volumes.

Block            Mass            Volume

  A                65.14 kg       103.38 L

  B                0.64 kg         100.64 L

  C                4.08 kg         104.08 L

  D                3.10 kg          103.10 L

  E                 3.53 kg         101.00 L

The density (ρ) is an intensive property resulting from dividing the mass (m) by the volume (V), that is, ρ = m / V

ρA = 65.14 kg / 103.38 L = 0.6301 kg/L

ρB = 0.64 kg / 100.64 L = 0.0064 kg/L

ρC = 4.08 kg / 104.08 L = 0.0392 kg/L

ρD = 3.10 kg / 103.10 L = 0.0301 kg/L

ρE = 3.53 kg / 101.00 L = 0.0350 kg/L

The order from least dense to most dense is B, D, E, C, A

4 0
3 years ago
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