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Elena-2011 [213]
2 years ago
14

A gas has a volume of 6.00 liters at a temperature of 300 K and a pressure of 1.00 atm what is the volume of the gas in liters a

t a temperature of 600 K and a pressure of 3.00 atm
Chemistry
1 answer:
Yanka [14]2 years ago
4 0

Answer:

V₂ = 4.00 L

Explanation:

Given that:

Volume (v1) = 6.00 L

Temperature (T1) = 300 K

Pressure (P1) = 1.00 atm

VOlume (V2) = unknown???

Temperature (T2) = 600 K

Pressure (P2) = 3.00 atm

Using combined gas law equation:

\dfrac{P_1V_1}{T_1}= \dfrac{P_2V_2}{T_2}

\dfrac{1 \times 6}{300} = \dfrac{3 \times V_2}{600}

\dfrac{1}{50} = \dfrac{1 \times V_2}{200}

200 = 50V₂

V₂ = 200/50

V₂ = 4.00 L

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What volume (in L) of H2 would be collected at 22.0oC and a pressure of 713 torr if 2.65 g of zinc react according to the equati
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Explanation:

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Read 2 more answers
When octane (C8H18) is burned in the presence of oxygen, the yield of products (carbon dioxide and water) is 87%. What mass of c
ahrayia [7]

Answer:

14.5g of CO₂ are produced

Explanation:

The reaction of octane with oxygen is:

C₈H₁₈ + 25/2O₂ → 8CO₂ + 9H₂O

<em>Where 1 mole of octane (Molar mass: 114.23g/mol) reacts with 25/2 moles of O₂ (Molar mass 32g/mol) to produce 8 moles of CO₂ and 9 moles of water.</em>

When 21.0 g of octane is burned with 19.0 g of oxygen gas you need to find <em>limiting reactant </em>to find how many moles of products are formed:

Octane: 21.0g ₓ (1mol / 114.23g) = 0.184 moles octane

Oxygen: 19.0g ₓ (1 mol / 32g) = 0.594 moles oxygen

For a complete reaction of 0.184 moles of octane you will need:

0.184 moles C₈H₁₈ ₓ (25/2 moles O₂ / 1 mole C₈H₁₈) = <em>2.3 moles of oxygen</em>

As you have just 0.594 moles of oxygen, <em>Oxygen is limiting reactant.</em>

Based on chemical equation, 25/2 of O₂ produce 8 moles of CO₂, that means theoretical yield of CO₂ with 0.594 moles of O₂ is:

0.594 moles O₂ ₓ (8 moles CO₂ / 25/2 moles O₂) = 0.380 moles of CO₂

But, as yield of products is 87%, moles produced of CO₂ are:

0.380 moles of CO₂ ₓ 87% = 0.331 moles CO₂ are produced.

As molar mass of CO₂ is 44g/mol, mass of CO₂ in 0.331 moles is:

0.331 moles CO₂ ₓ (44g / mol) =

<h3>14.5g of CO₂ are produced</h3>
6 0
3 years ago
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