Question

A gas has a volume of 6.00 liters at a temperature of 300 K and a pressure of 1.00 atm what is the volume of the gas in liters at a temperature of 600 K and a pressure of 3.00 atm

Answer 1

Answer:

V₂ = 4.00 L

Explanation:

Given that:

Volume (v1) = 6.00 L

Temperature (T1) = 300 K

Pressure (P1) = 1.00 atm

VOlume (V2) = unknown???

Temperature (T2) = 600 K

Pressure (P2) = 3.00 atm

Using combined gas law equation:

$\dfrac{P_1V_1}{T_1}= \dfrac{P_2V_2}{T_2}$

$\dfrac{1 \times 6}{300} = \dfrac{3 \times V_2}{600}$

$\dfrac{1}{50} = \dfrac{1 \times V_2}{200}$

200 = 50V₂

V₂ = 200/50

V₂ = 4.00 L