Answer:
194 V/m
Explanation:
In order to find electric field, we can use the formula of power density
i.e Pd = E^2 / Z
where:
Pd = power density in W/m^2
E = electric field strength in V/m
Z = impedance of free space = 120 * π
E = sqrt(Pd * Z)
-----> re-arranging it for E
before solving, convert Pd unit into W/m^2
Pd= 5mW/cm^2 = 50 W/m^2
Solving for E:
E= sqrt(50 * 120 * π)
E = 137.3 V/m
the above value is RMS value
In order to find the peak amplitude of the oscillating field will therefore be 137.3 * sqrt(2) = 194 V/m
Option 4 is your best answer, or letter B, because it has better work efficiencies than the other options and has a price that is in the middle of too costly and cheap,
hope this answer helps you out
To solve this problem it is necessary to apply the equations related to the law of Maus.
By the law of Maus we know that
Where,
= Intesity of incident light
I = Intensity of polarized light
With our values we have that
6V/m
Then
Therefore the maximum value of the transmitted E vector is 3V/m
This is the reason why dimensional analysis is very important. It is a technique used that only involves operations with units. You disregard the quantities first. The concept is to make sure that the final answer of your calculations must be consistent of what is asked. Similar units are cancelled when they appear both on the numerator and denominator side. If the mathematicians used this, they could've prevented the crash from happening. What good would the calculations bring if you are not consistent with the units?
Answer:
Explanation:
For first overtone
Standing waves will be formed lengthwise and breadth-wise in the enclosures having dimension of .75m x 1.5 m
A ) For the formation of lowest two frequencies formed by standing waves along the breadth , fundamental note and first overtone may be considered.
For fundamental note ,
the condition is
wave length λ = 2L = 2 x 0.75 m
λ = 1.5 m
frequency n = v / λ
= 343 / 1.5
= 229 Hz approx
For first overtone
λ = L = 0.75m
frequency n = v / λ
n = 343 / 0.75
= 457 Hz approx
B)
For the formation of lowest two frequencies formed by standing waves along the length , fundamental note and first overtone may be considered.
For fundamental note ,
the condition is
wave length λ = 2L = 2 x 1.5 m
λ = 3 m
frequency n = v / λ
= 343 / 3
= 114 Hz approx
frequency n = v / λ
n = 343 / 1.5
= 229 Hz approx
