Answer:
The acceleration at the moment the train speed reaches 52 kilometers per hour is approximately 1.826 meters per square second.
Explanation:
According to Rotational Physics, the total acceleration of the train rounding the horizontal turn is a combination of tangential (
) and radial accelerations (
), measured in meters per square second. The former one represents the change in the magnitude of the velocity, whereas the latter one represents the change in its direction. By definition of magnitude and Pythagorean Theorem we get that magnitude of total acceleration (
), measured in meters per square second, is:
(Eq. 1)
Magnitudes of tangential and radial accelerations are determined by using the following formulas:
(Eq. 1)
(Eq. 2)
Where:
, 
- Initial and final speeds, measured in meters per second.
- Time, measured in seconds.
- Radius, measured in meters.
If we know that 
, 
, 
and 
, then the magnitude of the total acceleration when the train speed reaches 52 kilometers per hour is:
The acceleration at the moment the train speed reaches 52 kilometers per hour is approximately 1.826 meters per square second.
Answer:
The field of view is reduced.
Explanation:
Given that,
The field of view for every resultant magnification like you change objectives from 4 to 10 to 43.
We know that,
Field of view :
When the view is observed at a point in a defined field then these field called field of view.
The normal angle of field of view is 90°.
The formula of field of view is define as,
We can say that,
The field of view is inversely proportional to the magnification.
When magnification is low then field of view will be large.
When magnification is higher then field of view will be small .
According to question,
When the magnification adjust from 4 to 10 to 43, the field of view is reduced.
Hence, The field of view is reduced.
Answer:
I know I am a very good answerable teacher but I can't answer this question I don't know what
Answer:
The direction of the force at A and B is perpendicular to the walls of the container.
The direction of the force at C is down.
The direction of the force in D is up
The direction of the force at E is to the left.
The attached figure shows the forces exerted by the water at points A, B, C, D and E.
Explanation:
The water is in contact with the bowl and with the fish. It exercises at points A, B, C, D and E, but the direction is different from the force.
The fish has a buoyant force on the water and that direction is up. The direction of at point D is up.
The column of water on the fish has a downward force, therefore the direction of the force at point C is down. The water column to the right of the fish has a force to the left, and the direction at point E is to the left.
The water will exert a force on the walls of the container and this force at points A and B is a on the walls of the container.
