Michael has a substance that he puts in Container 1. The substance has a volume of 5 cubic meters. He then puts the substance in
1 answer:
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To solve this problem we will apply the two concepts mentioned. To find the constant we will apply Hooke's law, and to find the period we will apply the relationship between the mass and the spring constant. Let us begin,
PART A) For this section we will use Hooke's law. In turn, since the force applied is equivalent to weight, we will use Newton's law for which weight is defined as the product between mass and gravity. This weight is equal to the Spring Force.
Here,
k = Spring constant
= Displacement
F = Force, the same as the Weight (mg)
Then we have that
Therefore the spring constant is 13.23N/m
PART B) To find the period of oscillation, the relationship that allows us to find is given by the following mathematical function,
Here
m = mass
k = Spring constant
Replacing,
Therefore the period of the oscillation is 0.491s
Answer:
Explanation:
The given data :-
- Diameter of rod AB ( d₁ ) = 200 mm.
- Diameter of rod BC ( d₂ ) = 150 mm.
- The linear co-efficient of thermal expansion of copper ( ∝ ) = 1.6 × 10⁻⁶ /°C
- The young's modulus of elasticity of copper ( E ) = 120 GPa = 120 × 10³ MPa.
- Consider the required temperature increase to close the gap at C = T °C
- Consider the change in length of the rod = бL
Solution :-