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aleksley [76]
2 years ago
10

5.(06.04B MC)

Chemistry
1 answer:
NARA [144]2 years ago
7 0

Answer:

Explanation:

1. The reaction will proceed backward, shifting the equilibrium position to the left.

2. The reaction will proceed forward, shifting the equilibrium position to the right.

3. Either add more of the products ( H2O or Cl2) or remove the reactant (HCl or O2)

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Answer: I dont take L´s. Only W´s so ha!!!

Explanation: Lol just messin with ya. I actually dont know what your question is but have a good one, and stay safe!! :))

5 0
3 years ago
The inca "City of the sun"was ​
SpyIntel [72]
The Inca “City of the Sun” was the city of Cuzco
7 0
3 years ago
(5.0 m3) ( 7.5 mmHg) = (P)(4.0m3)
anzhelika [568]

It looks like we are solving for a pressure.  All that is required is some algebraic manipulation to find our pressure in mmHg.

Given:

(5.0 m³)(7.5 mmHg) = (P)(4.0m³)

Multiply:

37.5 = 4.0P

Divide:

9.375 = P

P = 9.4 mmHg (remember sig figs)

<h3>Answer:</h3>

9.4 mmHg

7 0
3 years ago
Suppose a new group 5A element is discovered. Photoelectron spectroscopy (PES) reveals that its last two peaks occur at 1370 kJ/
iren2701 [21]

Answer: The average valence electron energy (AVEE) of this element =

1014.2 KJ/ mol  or  1.0142mJ/mol.

Explanation:

The average valence electron energy =  (number of electrons in s subshell  x  Ionization energy of that subshell) + (number of electrons in p subshell  x  Ionization energy of that subshell) / total number of electrons in both subshells of the valence shells.

The 5A elements are non-metals like Nitrogen and Phosphorus with the metallic character increasing as you go down the group, So a new 5A element will have characteristics of its group with 5 valence electron in its outermost shell represented as ns2 np3

Therefore  the average valence electron energy (AVEE) of this element will be calculated as

The average valence electron energy = (2 x 1370  kJ/mol + 3 x 777 kJ/mol.) / 5

2740+2331/ 5 =5071/5

=1014.2 KJ/ mol  or  1.0142mJ/mol.

5 0
3 years ago
Which of the following solutions is a good buffer system?A solution that is 0.10 M HCN and 0.10 M NaClA solution that is 0.10 M
patriot [66]

Answer:

A solution that is 0.10 M HCN and 0.10 M LiCN

Explanation:

  • A good buffer system contains a weak acid and its salt or a weak base and its salt.
  • In this case; A solution that is 0.10 M HCN and 0.10 M LiCN, would make a good buffer system.
  • HCN is a weak acid, while LiCN is a salt of the weak acid, that is, CN- conjugate of the acid.
8 0
3 years ago
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