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3 years ago

Please help I really appreciate it thank you ❤️

Chemistry

1 answer:

Feliz [49]3 years ago

3 0

II. sulfur (S) and carbon (C)

and

III. fluorine (F) and oxygen (O)

will form covalent bonds, so the answer will be:

e. II and III

Explanation:

To know is what type of bond is formed between atoms we need to look at the electronegativity difference between the atoms.

If the electronegativity difference is less than 0.4 there is a nonpolar covalent bond.

If the electronegativity difference is between 0.4 and 1.8 there is a polar covalent bond. (if is a metal involved we consider the bond to be ionic)

If the electronegativity difference is greater then 1.8 there is an ionic bond.

We have the following cases:

I. lithium (Li) and sulfur (S)

electronegativity difference = 2.5 (S) - 1 (Li) = 1.5 but because there is a metal involved the bond will be ionic

II. sulfur (S) and carbon (C)

electronegativity difference = 2.5 (S) - 2.5 (C) = 0 so the bond will be nonpolar covalent

III. fluorine (F) and oxygen (O)

electronegativity difference = 4 (F) - 3.5 (O) = 0.5 so the bond will be polar covalent bond.

Learn more about:

covalent and ionic bonds

brainly.com/question/1802971

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You want to know how many moles of gas your lungs can hold. You start off with a balloon that has 1.4 moles of gas and occupies

Mrrafil [7]

Number of moles : n₂ = 1.775 moles

<h3>Further explanation</h3>

Given

Moles = n₁ = 1.4

Volume = V₁=22.4 L

V₂=28.4 L

Required

Moles-n₂

Solution

Avogadro's hypothesis, at the same temperature and pressure, the ratio of gas volume will be equal to the ratio of gas moles

The ratio of gas volume will be equal to the ratio of gas moles

$\tt \dfrac{V_1}{V_2}=\dfrac{n_1}{n_2}$

Input the values :

n₂ = (V₂ x n₁)/V₁

n₂ = (28.4 x 1.4)/22.4

n₂ = 1.775 moles

4 0

3 years ago

Radio waves travel at the speed of light which is 3.00 x 10^8. How many minutes does it take for a radio message to reach saturn

ryzh [129]

Answer:

43.89 min

Explanation:

Given that:-

The speed of light = $3.00\times 10^8\ m/s$

The distance = $7.9\times 10^8\ km$

The conversion of distance in km to distance into m is shown below as:-

1 km = 1000 m

So,

Distance = $7.9\times 10^8\times 1000\ m=7.9\times 10^{11}\ m$

The relation between speed distance and time is shown below as:-

$Speed=\frac{Distance}{Time}$

Thus,

$3.00\times 10^8=\frac{7.9\times 10^{11}}{Time}$

$300000000\times time=10^{11}\times \:7.9\ s$

Time = 2633.33 seconds

Also, 1 s = 1/60 min

So,

Time= $\frac{2633.33}{60}\ min=43.89\ min$

3 0

3 years ago

What happens to the number of neutrons as you move across the table? <br><br> left to right

luda_lava [24]

Answer: The number of neutrons will increase as we move from left to right in a periodic table.

Explanation:

Atomic number is equal to the number of protons.

Mass number is the sum of number of neutrons and number of protons.

As we move from left to right, both the atomic number and mass number increases.

For example: As we move from Lithium to berrylium to boron to carbon to nitrogen to oxygen to fluorine to neon , the number of neutrons increase from 4 to 5 to 6 to 6 to 7 to 8 to 10 to 10.

Thus the number of neutrons will also increase as we move from left to right in a periodic table.

8 0

2 years ago

if a sample of gas at 25.2 c has a volume of 536mL at 637 torr, what will its volume be if the pressure is increased to 712 torr

nignag [31]

Considering ideal gas:
PV= RTn

T= 25.2°C = 298.2 K

P1= 637 torr = 0.8382 atm

V1= 536 mL = 0.536 L

:. R=0.082 atm.L/K.mol

:. n= (P1V1)/(RT) = ((0.8382 atm) x (0.536 L))/
((0.082 atmL/Kmol) x (298.2K))

:. n= O.0184 mol

Then,
P2= 712 torr = 0.936842 atm

V2 = RTn/P2 = [(0.082atmL/
Kmol) x (298.2K) x (0.0184mol) ]/(0.936842atm)

:.V2 = 0.4796 L
OR
V2 = 479.6 ml

6 0

3 years ago

If the molecule C6H12 does not contain a double bond, and there are no branches in it, what will its structure look like?

NARA [144]

I have attached a photo of the structure.
You can get better at solving problems like this by practicing a lot!

5 0

3 years ago