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4 years ago

Please help I really appreciate it thank you ❤️

Chemistry

1 answer:

Feliz [49]4 years ago

3 0

II. sulfur (S) and carbon (C)

and

III. fluorine (F) and oxygen (O)

will form covalent bonds, so the answer will be:

e. II and III

Explanation:

To know is what type of bond is formed between atoms we need to look at the electronegativity difference between the atoms.

If the electronegativity difference is less than 0.4 there is a nonpolar covalent bond.

If the electronegativity difference is between 0.4 and 1.8 there is a polar covalent bond. (if is a metal involved we consider the bond to be ionic)

If the electronegativity difference is greater then 1.8 there is an ionic bond.

We have the following cases:

I. lithium (Li) and sulfur (S)

electronegativity difference = 2.5 (S) - 1 (Li) = 1.5 but because there is a metal involved the bond will be ionic

II. sulfur (S) and carbon (C)

electronegativity difference = 2.5 (S) - 2.5 (C) = 0 so the bond will be nonpolar covalent

III. fluorine (F) and oxygen (O)

electronegativity difference = 4 (F) - 3.5 (O) = 0.5 so the bond will be polar covalent bond.

Learn more about:

covalent and ionic bonds

brainly.com/question/1802971

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5.00 ml of commercial bleach was diluted to 100.0 ml. 25.0 ml of the diluted sample was titrated with 4.56 ml of 0.100 m s2o3 2-

aev [14]

The solution would be like this for this specific problem:

4 NaOCl + S2O3{2-} + 2 OH{-} → 2 SO4{2-} + H2O + 4 NaCl

<span>(0.00456 L) x (0.100 mol/L S2O3{2-}) x (4 mol NaOCl / 1 mol S2O3{2-}) x (100.0 mL / 25 mL) x </span><span>
<span>(74.4422 g NaClO/mol) = 0.54313 g </span></span>

<span>(5.00 mL) x (1.08 g/mL) = 5.40 g solution </span>

(0.54313 g) / (5.40 g) = 0.101 = 10.1%

So, the average percent by mass of NaClO in the commercial bleach is 10.1%.

3 0

3 years ago

A buffer is prepared by adding 18.0 g of sodium acetate (ch3coona to 510 ml of a 0.160 m acetic acid (ch3cooh solution. determin

Nutka1998 [239]

Given:

mass of sodium acetate = 18.0 grams
volume of acetic acid = 510 ml
concentration of acetic acid = 0.160 M

Solve for the ph of the buffer:

pH = pKa + log [salt]/[acid]

pKa of acetic acid = 4.76
M of sodium acetate = 82g/mol
pH = 4.76 + log [18g/82g/mol] / [0.160M*(510/1000)]
pH = 5.19

4 0

3 years ago

8.7351 x 10-3 to ordinary notation:

BlackZzzverrR [31]

The answer to this question is 8735.1

3 0

3 years ago

.400 moles of CO2 gas are confined in a 5.00-liter container at 25 °C. Calculate the pressure exerted in atmospheres and mm Hg.

solong [7]

The pressure exerted by 0.400 moles of carbon dioxide in a 5.00 Liter container at 25 °C would be 1.9563 atm or 1486.788 mm Hg.

<h3>The ideal gas law</h3>

According to the ideal gas law, the product of the pressure and volume of a gas is a constant.

This can be mathematically expressed as:

pv = nRT

Where:

p = pressure of the gas

v = volume

n = number of moles

R = Rydberg constant (0.08206 L•atm•mol-1K)

T = temperature.

In this case:

p is what we are looking for.

v = 5.00 L

n = 0.400 moles

T = 25 + 273

= 298 K

Now, let's make p the subject of the formula of the equation.

p = nRT/v

= 0.400 x 0.08206 x 298/5

= 1.9563 atm

Recall that: 1 atm = 760 mm Hg

Thus:

1.9563 atm = 1.9563 x 760 mm Hg

= 1486.788 mm Hg

In other words, the pressure exerted by the gas in atm is 1.9563 atm and in mm HG is 1486.788 mm Hg.

More on the ideal gas law can be found here: brainly.com/question/28257995

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8 0

1 year ago

Date:

WARRIOR [948]

Answer:

Explanation:

3 0

3 years ago

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