I think that the answer is 0.49
Answer:
Option C
Explanation:
When you perform a experiment to test your hypothesis (your educated guess on what you think will happen) you complete trials to find data that is reliable and valid so you are only getting the best possible results. After you complete the experiment you write your conclusion which is when you take the data and you say if the data supported your hypothesis, if you did guess correctly at the beginning of the experiment. Which means the answer is option C "the conclusions tell why the data support or reject the hypothesis."
Hope this helps.
Answer:
0.23 V.
Explanation:
<em>∵ ΔG° = -RT lnK.</em>
∴ ΔG° = -RTlnK = -(8.314 J/mol)(298 K) ln(7.3 × 10⁷) = - 44.86 x 10³ J/mol.
<em>∵ ΔG° = - nFE°</em>
∴ E° = - ΔG°/nF = - (- 44.86 x 10³ J/mol)/(2 x 96500 s.A/mol) = 0.2324 V ≅ 0.23 V.
<h2><u>Full Question:</u></h2>
In hemoglobin, a single amino acid change at position 6 from Glu to Val has major consequences on hemoglobin structure that makes the molecule defective leading to sickle cell anemia. Predict whether the following hypothetical change would or would not have a major effect at position 6. Briefly explain (1-2 sentences). Glu to Leu Hint: Look at the structures of the R groups and consider their chemical properties
<h2><u>Answer:</u></h2>
The structure of the haemoglobin, hence the RBC won't be same as normal.
<h3><u>Explanation:</u></h3>
Both the leucine and glutamic acid are alpha amino acids which have an alpha carboxylic acid group and an alpha amino group. The variable in case of glutamic acid is propyl acid while the variable in case of leucine is isobutyl.
The glutamic acid is the normal amino acid of the 6th position of Beta chain of hemoglobin. Its an acid group, so can form bonds with another base inside the haemoglobin, or can form other hydrogen bonds. But the isobutyl group is an alkyl group. So it doesn't have that much effect in the recovering the structure, and sickle cell anemia prevails.
