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3 years ago

Provide an example of a Food Chain.

Chemistry

1 answer:

VikaD [51]3 years ago

5 0

Answer: Diamond is the name ^-^

A food chain only follows just one path as animals find food. eg: A hawk eats a snake, which has eaten a frog, which has eaten a grasshopper, which has eaten grass. A food web shows the many different paths plants and animals are connected. eg: A hawk might also eat a mouse, a squirrel, a frog or some other animal.

Hope this helps ^_^

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Determine the number of protons, neutrons, and electrons in the following isotopes that are used in medical diagnoses: (a) atomi

il63 [147K]

Answer:

7-c=760

Explanation:

the answer is 7-c=7698

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3 years ago

All of the Gathered in an investigation must be recorded. (Fill in the blank)

Zigmanuir [339]

The answer is "Incidents"

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3 years ago

What type of isomers are ch3ch2och3 and ch3ch2ch2oh?

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Functional isomers
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4 years ago

How many liters of 1.0 M HCl do you need to neutralize 2.0 L of 3.0 M NaOH? How many liters of 1.0 M HCl do you need to neutrali

Kruka [31]

Answer:

For 1: The volume of HCl required is 6 L.

For 2: The volume of HCl required is 9 L.

For 3: The volume of sulfuric acid required is 4.5 L.

Explanation:

To calculate the volume of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$ ......(1)

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base

For 1:

We are given:

$n_1=1\\M_1=1M\\V_1=?L\\n_2=1\\M_2=3.0M\\V_2=2.0L$

Putting values in equation 1, we get:

$1\times 1\times V_1=1\times 3\times 2\\\\V_1=6L$

Hence, the volume of HCl required is 6 L.

For 2:

We are given:

$n_1=1\\M_1=1M\\V_1=?L\\n_2=2\\M_2=3.0M\\V_2=1.5L$

Putting values in equation 1, we get:

$1\times 1\times V_1=2\times 3.0\times 1.5\\\\V_1=9L$

Hence, the volume of HCl required is 9 L.

For 3:

To calculate the volume of acid, we use the equation:

$N_1V_1=N_2V_2$

where,

$N_1\text{ and }V_1$ are the normality and volume of acid

$N_2\text{ and }V_2$ are the normality and volume of base

We are given:

$N_1=1.0N\\V_1=?L\\N_2=3.0N\\V_2=1.5L$

Putting values in above equation, we get:

$1.0\times V_1=3.0\times 1.5\\\\V_1=4.5L$

Hence, the volume of sulfuric acid required is 4.5 L.

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3 years ago

When you climb a rope you change? energy into? energy

Afina-wow [57]

You have potential energy to begin with and then you change it into Kinetic energy (or the energy of motion). Once you reach the top of the rope however you will again have potential energy.

3 0

3 years ago

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