Answer:
The percent isotopic abundance of Ir-193 is 60.85 %
The percent isotopic abundance of Ir-191 is 39.15 %
Explanation:
we know there are two naturally occurring isotopes of iridium, Ir-191 and Ir-193
First of all we will set the fraction for both isotopes
X for the isotopes having mass 193
1-x for isotopes having mass 191
The average atomic mass is 192.217
we will use the following equation,
193x + 191(1-x) = 192.217
193x + 191 - 191x = 192.217
193x- 191x = 192.217 - 191
2x = 1.217
x= 1.217/2
x= 0.6085
0.6085 × 100 = 60.85 %
60.85% is abundance of Ir-193 because we solve the fraction x.
now we will calculate the abundance of Ir-191.
(1-x)
1-0.6085 =0.3915
0.3915× 100= 39.15 %
Typically kinetic energy changes is passed through objects when it crashes
Answer:
T° freezing solution → -11.3°C
T° boiling solution → 103.1 °C
Explanation:
Assuming 100 % dissociation, we must find the i, Van't Hoff factor which means "the ions that are dissolved in solution"
This salt dissociates as this:
SnCl₄ (aq) → 1Sn⁴⁺ (aq) + 4Cl⁻ (aq) (so i =5)
The formula for the colligative property of freezing point depression and boiling point elevation are:
ΔT = Kf . m . i
where ΔT = T° freezing pure solvent - T° freezing solution
ΔT = Kb . m . i
where ΔT = T° boiling solution - T° boiling pure solvent
Freezing point depression:
0° - T° freezing solution = 1.86°C/m . 1.22 m . 5
T° freezing solution = - (1.86°C/m . 1.22 m . 5) → -11.3°C
Boiling point elevation:
T° boiling solution - 100°C = 0.512 °C/m . 1.22 m . 5
T° boiling solution = (0.512 °C/m . 1.22 m . 5) + 100°C → 103.1 °C
Just reorder the equation
Density= mass/volume
Answer:
c) FAD is the oxidizing agent
Explanation:
The β-oxidation is a catabolic process where fatty acids are degraded into a final product: Acetil-CoA. In order this process occurres, the fatty acid chain is being removed from a pair of carbon atoms on each cycle
Before the β-oxidation takes place, the fatty acid molecule should be activated, so it can go through the mitochondrial membrane into (via a carnitine translocator)
Once the activated molecule is inside the mitochondrial matrix, it can go through the β-oxidation: the first step is the oxidation of the fatty acid, with the enzyme Acyl-CoA-dehydrogenase (this enzyme catalyzes the creation of a double bond between carbon-2 and carbon-3.
This enzyme has attached a coenzyme: FAD, which takes the electrons (from the fatty acid oxidation) and becomes a reduced component: FADH2:
Acyl-CoA + FAD ↔ trans-Δ2-enoyl-CoA + FADH2
