The correct answers are:
13 + 3 ÷ 3 = 1(13 + 3 ÷ 3)
13 + 3 ÷ 3 = 13 + 1
13 + 3 ÷ 3 = 13 + 3 ÷ 3 + 0
Let's look into them one by one:
13 + 3 ÷ 3 = 1(13 + 3 ÷ 3)
As anything multiplied by one will not have changes in value, this is correct.
13 + 3 ÷ 3 = 13+(3÷3) = 13 + 1
As 3÷3 is 1,this is also correct.
13 + 3 ÷ 3 = 13 + 3 ÷ 3 + 0
As anything plus zero will not have a chnage in value, this is correct.
The incorrect option:
13 + 3 ÷ 3 ≠ 16 ÷ 3
Unless there are brackets indicating addition has to be done first, devision comes before addition hence this is not correct.
Hope it helps!
Answer:
2.26
Step-by-step explanation:
brainliest pls
The correct answr is 24 3/4 just took the test
Answer:
The profit form a strawberry smoothie is of $26.32, and the profit from a chocolate smoothie is of $26.32.
Step-by-step explanation:
This question can be solved by a system of equations.
I am going to say that:
x is the profit from a strawberry smoothie.
y is the profit from a chocolate smoothie.
Se sold 24 strawberry smoothies and 5 chocolate smoothies, for a profit of $200.
This means that: 24x + 5y = 200
Today, she made a profit of $300 by selling 30 strawberry smoothies and 11 chocolate smoothies.
This means that 30x + 11y = 300
So we have the following system:
24x + 5y = 200
30x + 11y = 300
I will use the addition method, multiplying the first equation by 5 and the second by -4. So
120x + 25y = 1000
-120x - 44y = -1500
So, adding both equations, we get:
And for x:
The profit form a strawberry smoothie is of $26.32, and the profit from a chocolate smoothie is of $26.32.
Answer:
6082.12
Step-by-step explanation:
well the equation of an area of a circle is is pie*R^2
so it could be 3.14*44^2 which honestly would not complete to any of your answers i googled the equation and it said it was 6082.12 it shows you how to do it too.
please look at it ill leave the website
https://www.google.com/search?q=area+of+a+circle&rlz=1C1GCEU_enUS848US848&oq=area+of+a+circle&aqs=chrome.0.0j69i60l2j0l3.2687j0j7&sourceid=chrome&ie=UTF-8&safe=active&ssui=on
Or you look up area of a circle and a converter to show up thanks