Answer:
a. infinite solutions, answer is x = 30, identity equation
b. no solution, a contradiction equation
c. no solution, a contradiction equation
Step-by-step explanation:
Treat the matrices on the right side of each equation like you would a constant.
Let 2<em>X</em> + <em>Y</em> = <em>A</em> and 3<em>X</em> - 4<em>Y</em> = <em>B</em>.
Then you can eliminate <em>Y</em> by taking the sum
4<em>A</em> + <em>B</em> = 4 (2<em>X</em> + <em>Y</em>) + (3<em>X</em> - 4<em>Y</em>) = 11<em>X</em>
==> <em>X</em> = (4<em>A</em> + <em>B</em>)/11
Similarly, you can eliminate <em>X</em> by using
-3<em>A</em> + 2<em>B</em> = -3 (2<em>X</em> + <em>Y</em>) + 2 (3<em>X</em> - 4<em>Y</em>) = -11<em>Y</em>
==> <em>Y</em> = (3<em>A</em> - 2<em>B</em>)/11
It follows that
Similarly, you would find
You can solve the second system in the same fashion. You would end up with
4/3 because 3/3 is 1 and 4/3 is 1 1/3
The answer is 101
100 squared is 10,000
Then form an equation
100u-100=10,000
+100 +100
100u=10,100
divide by 100 on both sides
and you get 101 as the answer