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3 years ago

"A problem involves a car of mass m going down a track from a height H, and round a loop of radius r. The loop is frictionless.

Physics

1 answer:

neonofarm [45]3 years ago

4 0

Answer:

Explanation:

At the topmost position, the car does not have zero velocity but it has velocity of v so that

v² /r = g or centripetal acceleration should be equal to g ( 9.8 )

Considering that, the car must fall from a height of 2r + h where

mgh = 1/2 mv²

= 1/2 m gr

So h = r/2

Hence the ball must fall from a height of

2r + r /2

= 2.5 r . So that it can provide velocity of v at the top where

v² / r = g .

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You are driving at 35 m/s east and notice another car that is initially located 462 m in front of you and is moving east at 25 m

GaryK [48]

The easiest way to answer this question is by realizing there are relating the velocities of the two cars. To tackle this problem, you have to understand the picture. Car 1 travels at 35m/s and Car 2 travels at 25m/s. Based on relative velocities, we can understand that Car 1 travels 10m/s faster than Car 2 every second. So we can interpret Car 1's relative velocity to Car 2 as 10m/s. Car 1 needs to travel 10m/s till a point of catching up to Car 2 which is 462m away.

v = 10m/s

d = 462m

v = d/t

(10) = (462)/t

t = 46.2s

So it takes 46.2 seconds for Car 1 to catch up to Car 2, but the question is asking how far does Car 1 travel to catch up. So we have to use Car 1's velocity and not the relative velocity:

v = 35m/s

v = d/t

(35) = d/(46.2)

d = 1617m

Car 1 traveled a total distance of 1617m.

7 0

4 years ago

Read 2 more answers

Yasmin is testing an unknown solution to determine whether it is an acid or a base. She dips red litmus paper in the solution. I

victus00 [196]

The correct answer is D) It is not a base

7 0

3 years ago

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Se deja resbalar por un plano inclinado de 30° un cuerpo de 15kg. Calcular la aceleración con la que desciende suponiendo que no

kupik [55]

Answer:

$4.9 m/s^2$

Explanation:

In order to find the acceleration of the block, we have to find the net force acting on it along the direction parallel to the incline.

However, there is only one force acting on the block along this direction: it is the component of the weight parallel to the plane, given by

$mg sin \theta$

where

m = 15 kg is the mass of the block

$g=9.8 m/s^2$ is the acceleration of gravity

$\theta=30^{\circ}$ is the angle of the incline

According to Newton's second law, the net force is proportional to the acceleration, a:

$F=ma$

So we can write:

$ma = mg sin \theta$

And so, the acceleration is:

$a=g sin \theta = (9.8)(sin 30^{\circ})=4.9 m/s^2$

7 0

3 years ago

A ball is dropped off the top of a 35 meter tall building. How fast will it be going when it reaches

4vir4ik [10]

1 Times 35 that’s your answer

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4 years ago

A t-rated switch may be used to (its/a) ______ current capacity when controlling an incandescent lighting load.

jok3333 [9.3K]

<u>Rated </u>

A t-rated switch may be used to (its/a) <u>Rated</u> current capacity current capacity when controlling an incandescent lighting load.

<h3>What is "current rating"?</h3>

The greatest current that a fuse is rated to carry for an infinite duration without significantly degrading the fuse element is known as the current rating.
There is also a large selection of power switching transistors that have voltage ratings well over 1000V and current ratings up to several hundred amps.

<h3>What does the term "rated current" mean?</h3>

When an electrical device receives its rated voltage and outputs its rated power, it flows at its rated current.
So, when a device is designed for a certain amperage, that amperage is referred to as the equipment's rated current.

<h3>What does electrical "rated" mean?</h3>

An electrical appliance's rating reveals the voltage range at which it is intended to operate as well as the current consumption at that range.
These numbers are typically shown on a rating plate that is fastened to the device, such as 230 volts, 3 amps.

To learn more about current capacity visit:

brainly.com/question/27987428

#SPJ4

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2 years ago