Answer:
(a) a = (2i + 4.5j) m/s^2
(b) r = ro + vot + (1/2)at^2
Explanation:
(a) The acceleration of the particle is given by:
vo: initial velocity = (3.00i -2.00j) m/s
v: final velocity = (9.00i + 7.00j) m/s
t = 3s
by replacing the values of the vectors and time you obtain:
(b) The position vector is given by:
where vo = (3.00i -2.00j) m/s and a = (2.00i + 4.50j)m/s^2
Answer:
Explanation:
Given:
Mass of the cannonball (M) = 20 kg
Mass of the marble (m) = 0.002 kg
Distance between the cannonball and marble (d) = 0.30 m
Universal gravitational constant (G) =
Now, we know that, the gravitational force (F) acting between two bodies of masses (m) and (M) separated by a distance (d) is given as:
Plug in the given values and solve for 'F'. This gives,
The same force is experienced by both cannonball and marble.
Therefore, the gravitational force of the marble is