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3 years ago

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A ball of mass 0.5 kg is released from rest at a height of 30 m. How fast is it going when it hits the ground? Acceleration due

to gravity is g = 9.8 m/s²

1 answer:

MArishka [77]3 years ago

4 0

The answer is attached.

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Slow-moving vehicles are prohibited from traveling on expressways or on roadways with a minimum posted speed limit greater than

Bumek [7]

<span>Slow-moving vehicles are prohibited from traveling on expressways or on roadways with a minimum posted speed limit greater than 40mph, and should use the right lane of travel on divided highways.
As slow moving vehicles should use the right lane, fast moving vehicles should use the left lane.
Before start driving, we should learn all the guidelines and rules for this, to avoid any type of inconvenience.</span>

7 0

3 years ago

2. Four resistors of 2 ohm each are connected first in series and then in parallel with a battery.Find the ratio of electric cur

Serjik [45]

Answer:

Ratio of series current to parallel

= 1 : 8

Explanation:

Total resistance Rt

For series, Rt = 2+2+2+2 = 4ohms

For parallel, 1/Rt = 1/2 + 1/2 + 1/2 + 1/2

1/Rt = 4/2, Rt = 2/4 ohms.

If we use a 1V battery, then,

I = V/Rt

I = 1/4 = 0.25 ampere for series arrangement.

I = 1/0.5 = 2 ohms.

Ratio of current of series to parallel = 0.25 : 2

= 1 : 8

4 0

3 years ago

Read 2 more answers

A flap of tissue that prevents blood from flowing back is a(n)________ .

ioda

A valve is a flap of tissue that prevents blood from flowing back

6 0

3 years ago

The speed of sound in air is 345 m/s. A tuning fork vibrates above the open end of a sound resonance tube. If sound waves have w

Delvig [45]

To develop this problem it is necessary to apply the concept of Frequency based on speed and wavelength.

According to the definition the frequency can be expressed as

$f = \frac{v}{\lambda}$

Where,

v = Velocity

$\lambda =$ Wavelength

Our value are given by,

v = 345m/s

$\lambda = 63cm$

Replacing

$f = \frac{345}{0.63}$

$f = 547.61Hz$

Therefore the frequency of the tuning fork is 547.61Hz

6 0

3 years ago

Suppose a particle moves along a straight line with velocity v(t)=t2e−2tv(t)=t2e−2t meters per second after t seconds. How many

dimulka [17.4K]

Explanation:

It is given that,

Velocity of the particle moving in straight line is :

$v(t)=t^2e^{-2t}\ m/s$

We need to find the distance (x) traveled by the particle during the first t seconds. It is given by :

$x=\int\limits {v.dt}$

$x=\int\limits {t^2e^{-2t}dt}$

Using by parts integration, we get the value of x as :

$x=\dfrac{-(2t^2+2t+1)e^{-2t}}{4}\ meters$

Hence, this is the required solution.

6 0

3 years ago