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Leya [2.2K]
4 years ago
13

A certain substance X decomposes. It is found that 50% of X remains after 100 minutes. How much X remains after 200 minutes if t

he reaction order with respect to X is a) zero order b) first order c) second order
Chemistry
1 answer:
raketka [301]4 years ago
8 0
Zero Order: t(1/2) = [A]o/(2*k), so k = [A]o/(2 * t(1/2)), where t(1/2) = 100 min. and [A]o=100% So incorporate condition. A= - .0005 x 200 mins+1 of introductory fixation approaches zero percent. 
Initially Order: Half-life condition k=.00693 remaining with 100 mins half life 
Coordinate condition lnx= - .00693x200mins + ln 1 squares with lnx= - 1.386. Take to the e to counteract ln so x=.25 or 25% 
Second Order Initial Concentration of 1, half-existence of 100 mins. K= .01. Coordinate condition 1/x = .01 x 200 +1. X= 33.3%
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Explanation:

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Suppose now that you wanted to determine the density of a small crystal to confirm that it is phosphorus. From the literature, y
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Answer:

Volume of CHCl_3   = 15.31 mL

Volume of CHBr_3 = 4.69 mL

Explanation:

Given that:

the density of the mixture = 1.82 g/mL

From the density of the pure samples

The density of CHCl_3 = 1.492 g/mL

The density of CHBr_3 = 2.890 g/mL

The total volume of the liquid mixture = 20.0 mL

Suppose the volume of  CHCl_3 = P ml

and the volume of CHBr_3 = Q ml

the sum of their volumes should be equal to the total volume of the mixture

P \ ml + Q \ ml = 20 ml  ----- (1)

However, we know that Density = mass/volume

∴ mass = density × volume

The equation can now be expressed as:

\mathtt{(Density \ of  \ CHCl_3 \times Vol. \ of  \ CHCl_3 ) + (Density  \  of \  CHBr_3  \times \ volume \ of \ CHBr_3)} = \mathtt{ (Density  \ of \ mixture \times volume \ of \ the \ mixture)}

1.492 g/mL × P mL + 2.890 g/mL × Q mL = 1.82 g/mL × 20 mL  ---- (2)

From equation (1) ;

let Q = 20 - P

The replace the value of P into equation (2)

1.492 g/mL × P mL + 2.890g/mL × (20 - P) mL = 1.82 g/mL × 20 mL

1.492 P g + 57.8g - 2.890 P g =  36.4g

1.492 P g - 2.890 P g = 36.4g - 57.8g

-1.398 P g = -21.4g

P = -21.4g/-1.398g

P = 15.31 mL

Q = 20 - P

Q = (20 - 15.31) mL

Q = 4.69 mL

∴

Volume of CHCl_3   = 15.31 mL

Volume of CHBr_3 = 4.69 mL

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ahrayia [7]

Answer:

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Explanation:

Temperature is the measure of thermal energy present in a given substance. It is a physical property of a matter which can be measured on the Celsius scale (°C), Fahrenheit scale (°F), and Kelvin scale (K).

<u>To convert Celsius (°C) to Fahrenheit (°F), we use the equation:</u>

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Given: On February 9, 1934,

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So,

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⇒ T₁ < T₂

<u>Therefore, Buffalo, NY was colder on February 9, 1934.</u>

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