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ehidna [41]
1 year ago
11

Given similar concentrations, the stronger acid corresponds to the lower pH. Comment on the relative strengths of the acids H3PO

4, H2PO4^– and H2PO4^2–
Chemistry
1 answer:
andreyandreev [35.5K]1 year ago
7 0

Answer:

H3PO4 is stronger than H2PO4- because

H3PO4 dissociation constant is 6.9×10^-3

H2PO4^- dissociation constant is 6.2×10^-8

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If rust is scraped off a nail, and the nail is shiny on the inside, the inside wasA.chemically changed also.B.not chemically cha
aliya0001 [1]

Answer: D.neither physically nor chemically changed.

Explanation:

A physical change is defined as a change in which there is alteration in shape, size etc. No new substance gets formed in these reactions.

Example: Melting of ice

A chemical change is defined as a change in which a change in chemical composition takes place. A new substance is formed in these reactions.

Example: Corrosion of iron

As the inside of the nail was still shiny and in same phase, that means it has not undergone any physical or chemical change.

3 0
3 years ago
An electron in an atom is known to be in a state with magnetic quantum number . What is the smallest possible value of the princ
nlexa [21]

Answer:

Hi

Each electron in an atom is characterized by four numbers that arise from the resolution of Schrödinger's equations. These numbers are called quantum numbers. Each energy level corresponds to a main known quantum number, which is represented by the letter n. This number gives an idea of the location of an energy level with respect to the nucleus. The higher n, the mayor will be the energy of that level and the farther away from the nucleus is removed.

In each energy level there may be sub-levels. Each of them is specified by another quantum number called secondary, specified with the letter l. The value of this quantum number can vary from zero to n-1. For example, in the first energy level, the quantum number can only take a value that is zero, while in the second level, it can take a value between zero or one. Then, it can be said that the values of the quantum number n indicate the size of the orbital, that is, its proximity to the nucleus; and the values of the quantum number l variables the orbital:

• If l = 0, the orbital is of type s.

• If l = 1, the orbitals are of type p.

• If l = 2, the orbitals are of type d.

• If l = 3, the orbitals are of type f.

Explanation:

8 0
3 years ago
A sample of sulfur has a mass of 232 grams. How many moles of sulfur are in the sample? 7.24 mol of S 7.235 mol of S 8.00 mol of
galben [10]

Answer:

7.235 mol of S are in the given sample

Explanation:

Number of mol calculated as follows:

Number of mol = amount in g / molar mass

Given that amount of sulfur = 232 grams.

Molar mass of sulfur = 32.065 g/ mol

Therefore the number of S is calculated as follows:

Number of mol = 232 grams/ 32.065 g/ mol

= 7.235 mol

7.235 mol of S are in the given sample

5 0
3 years ago
Read 2 more answers
HELP PLEASE. STRUGGLING. Which of the following is true in an acidic solution? A)The molarity of hydroxide is double the molarit
fredd [130]
The statement that would be held true for an acidic solution would be option C. The molarity or concentration of the hydronium ions would be more than that of the hydroxide ions. As the acidity of a solution increases as there is a greater amount of H+ or H3O+ ions present, within it. This is will give us a low pH and thus is quite acidic.

If the concentrations of the OH- and H3O+ are the same then the solution would be neutral, and if the opposite is true. The concentration of OH- is more than H3O+ than the solution would be basic.
3 0
3 years ago
How many atoms of Iodine are in a 12.75g sample of CaI2?
Inessa [10]

Answer is: 5.22·10²² atoms of Iodine.

m(CaI₂) = 12.75 g; mass of calcium iodide.

M(CaI₂) = 293.9 g/mol; molar mass of calcium iodide.

n(CaI₂) = m(CaI₂) ÷ M(CaI₂).

n(CaI₂) = 12.75 g ÷ 293.9 g/mol.

n(CaI₂) = 0.043 mol; amount of calcium iodide.

In one molecule of calcium iodide, there are two iodine atoms

n(I) = 2 · n(CaI₂).

n(I) = 0.086 mol; amount of iodine atoms.

Na = 6.022·10²³ 1/mol; Avogadro number.

N(I) = n(I) · Na.

N(I) = 0.086 mol · 6.022·10²³ 1/mol.

N(I) = 5.22·10²²; number of iodine atoms.

6 0
3 years ago
Read 2 more answers
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