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Lemur [1.5K]
4 years ago
9

Find the magnitude of the gravitational force a 68.4 kg person would experience while standing on the surface of earth with a ma

ss of 5.98 à 1024 kg and a radius of 6.37 à 106 m. the universal gravitational constant is 6.673 à 10â11 n · m2 /kg2 . answer in units of n.
Physics
1 answer:
luda_lava [24]4 years ago
6 0
Given: Mass of a person M = 68.4 Kg.

           Mass of earth Me = 5.98 x 10²⁴ Kg

           Radius of earth r = 6.37 x 10⁶ m

           G = 6.67 x 10⁻¹¹ N.m²/Kg²

Required: F = ?

Formula: F = GMeM/r²

               F = (6.67 x 10⁻¹¹ N.m²/Kg²)(5.98 x 10²⁴)(68.4 Kg)/(6.37 x 10⁶ m)²

               F = 672.41 N




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Given:

Parallax of Regulus, p = 0.042 arc seconds

Calculation:

When an observer changes their position, an apparent change in the object's position takes place. This change can be calculated using the angle ( or semi-angle) made by the observer and object i.e. the angle made between the two lines of observation from the object to the observer.

Thus from the relation of parallax of a celestial body we get:

S = 1/ tan p ≈ 1 / p

where S is the actual distance between the object and the observer

            p is the parallax angle observed

Here for Regulus, we get:

S = 1 / p

  = 1 / (0.042)                                     [ 1 parsecs = 1 arcseconds ]

  = 23.81 parsecs

We know that,

1 parsecs = 3.26 light-years = 206,000 AU

Converting the actual distance into light years we get:

23.81 parsecs = 23.81 × (3.26 light yrs) = 77.658 light-years

Therefore, the actual distance of Regulus from Earth is 23.81 parsecs which is 77.658 in light years.

Learn more about astronomical units here:

<u>brainly.com/question/16471213</u>

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Explanation:

that's just what I learned in school

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3 years ago
Rock at the top of a 20 m tall hill the rock has a mass of 10 kg how much potential energy does it have
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what volume of alcohol will have the same mass as 4.2m^3 of petrol? (density of alcohol 0.4kg/m^3 and petrol is 0.3kg/m^3)​
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Answer:

3.15m³

Explanation:

To solve this problem, let us first find the mass of the petrol from the given dimension.

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      We can now find the volume of the alcohol

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Mass of alcohol  = 1.26kg

Density of alcohol  = 0.4kgm⁻³  

  Volume of alcohol  = \frac{1.26}{0.4}   = 3.15m³

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