You can use the impulse momentum theorem and just subtract the two momenta.
P1 - P2 = (16-1.2)(11.5e4)=1702000Ns
If you first worked out the force and integrated it over time the result is the same
Answer:
If I understand correctly. Line B is parallel to the circle. Also, the angle is less than 90.
- The size of the circle determines.
- The diameter should not be fixed either.
Answer:
Maximum acceleration in the simple harmonic motion will be 
Explanation:
We have given amplitude of simple harmonic motion is A = 0.43 m
Time period of the oscillation is T = 3.9 sec
We have to find the maximum acceleration
For this we have to find the angular frequency
Angular frequency will be equal to 
Maximum acceleration is given by 
So maximum acceleration in the simple harmonic motion will be
a closed system does not allow matter or energy to pass through
Answer:
16 ohms
Explanation:
V=
I
⋅
R
where, V is the net potential difference in the circuit, I is the current in the circuit and R is the net resistance of the circuit.
In this case, V
=
240 volts, I
=
15 amperes.
240
=
15
⋅
R
⇒
R
=
240/
15
=
16 ohms
