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jenyasd209 [6]
3 years ago
6

If your mass, the mass of Earth, and the mass of everything in the solar system were twice as much as it is now, yet everything

stayed the same size, your weight on Earth woulda. quadruple. b. be the same. c. double. d. be eight times as much as now. e. none of the above
Physics
1 answer:
damaskus [11]3 years ago
3 0

Answer: a. Quadruple

Explanation:

Gravitational force = Gm1m2/r^2

(Where m1 is the mass of earth, m2 is my mass and r is the radius of earth and G is the gravity constant)

Weight = m2g

(Where g is the acceleration due to gravity)

Gm1m2/r^2 = m2g

Twice the masses

F = G(2m1)(2m2)/r^2

F = 4Gm1m2/r^2

The gravitational force has increased 4 times, this means that my weight on earth will quadruple

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When a 2.60-kg object is hung vertically on a certain light spring described by Hooke's law, the spring stretches 2.86 cm. (a) W
Goryan [66]

Answer:

a)  k = 891.82 N/m

b) e = 0.0143 m = 1.43 cm

c) W = 5.02 J

Explanation:

Step 1: Data given

Mass = 2.60 kg

the spring stretches 2.86 cm = 0.0286

Step 2: What is the force constant of the spring?

Force constant, k = force applied / extension produced  

k = (2.60kg * 9.81N/kg) / 0.0326 m

k = 891.82 N/m

b)  If the 2.60-kg object is removed, how far will the spring stretch if a 1.30-kg block is hung on it

Extension = F/k = (1.30 kg * 9.81) / 891.82 =  0.0143 m = 1.43 cm

Half the mass means half the extension

c) How much work must an external agent do to stretch the same spring 7.50 cm from its unstretched position?

W = average force used * distance

W = 1/2 * k*e * e = 1/2 k*e²  

W = 1/2 * 891.82 * (0.075)² = W = 5.02 J

5 0
3 years ago
A boy throws a snowball straight up in the air with an initial speed of 4.50 ft/s from a position 4.00 ft above the ground. The
IgorC [24]

Answer:

a) 0.658 seconds

b) 0.96 inches

Explanation:

v=u+at\\\Rightarrow 0=4.5-32.1\times t\\\Rightarrow \frac{-4.5}{-32.1}=t\\\Rightarrow t=0.14 \s

Time taken by the ball to reach the highest point is 0.14 seconds

s=ut+\frac{1}{2}at^2\\\Rightarrow s=4.5\times 0.14+\frac{1}{2}\times -32.1\times 0.14^2\\\Rightarrow s=0.315\ ft

The highest point reached by the snowball above its release point is 0.315 ft

Total height the snowball will fall is 4+0.315 = 4.315 ft

s=ut+\frac{1}{2}at^2\\\Rightarrow 4.315=0t+\frac{1}{2}\times 32.1\times t^2\\\Rightarrow t=\sqrt{\frac{4.315\times 2}{32.1}}\\\Rightarrow t=0.518\ s

The snowball will reach the bank at 0.14+0.518 = 0.658 seconds after it has been thrown

v=u+at\\\Rightarrow v=0+32.1\times 0.518\\\Rightarrow v=16.62\ ft/s

v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{0^2-16.62^2}{2\times -100\times 3.28}\\\Rightarrow s=0.42\ ft

The snowball goes 0.5-0.42 = 0.08 ft = 0.96 inches

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4 years ago
How many isotopes can an element have?
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 <span>The element with the greatest number of known stable isotopes is tin, with 10 stable isotopes. Including unstable isotopes, mercury, cesium, and barium are each known to have 40 isotopes. Theory predicts however that many unstable isotopes should exist which have not yet been discovered (especially on the neutron-rich side of the line of stability.)

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Answer:

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