1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Paul [167]
3 years ago
14

I WILL MARK BRAINLIEST!!ASAP!!! Wet Lab - Coulomb's Law lab from edge!!

Physics
2 answers:
love history [14]3 years ago
5 0
Help with what?????????
777dan777 [17]3 years ago
4 0

Answer:

idek to be honest

Explanation:

You might be interested in
Warm air rises because it has less ___________.
REY [17]

Answer:

because it is less dense than the surrounding air

Explanation:

5 0
3 years ago
Without using a micrometer screw gauge, how do I find the average diameter of a long piece of thin wire using a metre rule and a
Mice21 [21]

Answer:

Wind the long piece of thin wire around the uniform glass rod multiple times, find the length of the total diameters using the metre ruler, and divide by the number of times you wound it around the rod.

Explanation:

Since the diameter of one long piece of thin wire is too thin to be measured by a metre ruler, you can wind it multiple times and push it side by side to get a length you can measure.

For example, if you wound it around 20 times and the total length of 20 diameters of the wire side-by-side is 2.0 cm, one winding, which is the diameter would be 2.0cm ÷ 20 = 0.10cm or 1mm.

5 0
3 years ago
Consider a uniformly volume‑charged sphere of radius R and charge Q . What is the electric potential on the surface of the spher
VARVARA [1.3K]

To solve this problem we will start by applying the given load ratio, and we will rely on the two types of distances given. Later we will use Gauss's law and through its integrals, in which it is equivalent to the potential we will obtain its value in the center of the sphere. Since it is uniformly charged we have to,

\frac{Q'}{Q} = \frac{4\pi r^3}{4\pi R^3}

Q' = \frac{r^3}{R^3} Q

By Gauss Law

\phi = E \cdot 4\pi r^2

Here, E is the electric Field and is equal to

E = \frac{Q'}{\epsilon_0}

For \epsilon_0 being the Permeability constant at free space

Replacing with the previous value we have,

\phi = \frac{Qr^3}{\epsilon_0 R^3}

Then the value of the electric field is,

E = \frac{QR}{4\pi \epsilon_0 R^3}

Now potential

V = \int_0^R E\cdot dr'

V = - \frac{QR^2}{8\pi \epsilon_0 R^3}

V = -\frac{Q}{8 \pi \epsilon_0 R}

6 0
3 years ago
A hiker determines the length of a lake by listening for the echo of her shout reflected by a cliff at the far end of the lake.
ArbitrLikvidat [17]

Answer:

L = 499 m

Explanation:

  • If we assume that the speed of sound is constant, that travels along a straight line, and that the echo is instantaneous, we can find the total distance travelled by the sound, as follows, just applying the definition of average velocity:

       \Delta x = v_{s} * t = 343 m/s* 2.91 s = 998 m

  • If we assume that the time needed to reach to the cliff, is the same used for the return travel, the length of the lake will be exactly half of the total distance calculated:

        l_{lake} = \frac{\Delta x}{2} = \frac{998m}{2} = 499 m

  • The length of the lake is 499 m.
8 0
3 years ago
Which countries were considered the three major Axis Powers?
7nadin3 [17]
B. JAPAN, GERMANY, and ITALY

The main Axis powers were Japan, with Emperor Hirohito as leader; Germany, with Adolf Hitler as leader; and Italy, with Benito Mussolini as leader. They were all dictators.

The Axis powers began to form in 1936

15th October 1936 - Germany and Italy signed a friendship treaty - Rome-German Axis.
25th November 1936 - Germany and Japan signed a treaty against communism - Anti-Comintern Pact

22nd May 1939 - Germany and Italy signed a stronger alliance - Pact of Steel
27th September 1940 - Japan signed the Pact of Steel - It became known as the Tripartite Pact.
8 0
3 years ago
Other questions:
  • A bucket filled with water feels lighter while it is inside water<br>​
    14·2 answers
  • (I) At room temperature, an oxygen molecule, with mass of –26 5.31 10 kg, typically has a kinetic energy of about –21 6.21 10 J
    12·1 answer
  • What happens when a cell stops using energy?
    14·2 answers
  • A 50-kg box is being pushed along a horizontal surface. The coefficient of static friction between the box and the ground is 0.6
    12·1 answer
  • A boy throws a ball into the air at 10.2 m/s. Assuming that only gravity acts on the ball, how high does it rise, in m?
    7·1 answer
  • A jet airliner moving initially at 612 mph (with respect to the ground) to the east moves into a region where the wind is blowin
    11·1 answer
  • What are simple machines please?
    13·2 answers
  • A student drove to the university from her home and noted that the odometer reading of her car increased by 17.9 km. The trip to
    11·1 answer
  • Explain why selling cereal by mass rather then by volume be more fair to customers
    5·1 answer
  • Which of the following does NOT represent Newton’s second law? Question 20 options: a = m/Fnet m = Fnet/a Fnet = ma a = Fnet/m
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!