A hoop (I = MR2) of mass 3 kg and radius 1.1 m is rolling at a center-of-mass speed of 11 m/s. An external force does 842 J of w ork on the hoop. What is the new speed of the center of mass of the hoop (in m/s)? Round your answer to the nearest whole number.
1 answer:
Answer:
Explanation:
Since the hoop is rolling on the floor so its total kinetic energy is given as
now for pure rolling condition we will have
also we have
now we will have
now by work energy theorem we can say
now solve for final speed
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