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VikaD [51]
3 years ago
15

A student's pencil rolls off a desk and lands 0.47 m away from the edge of the

Physics
1 answer:
GaryK [48]3 years ago
6 0

Answer: 56

Explanation: i took the quiz

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in a football game, the kicker kicks a football a horizontal distance of 43 yards if the ball lands 3.9 seconds later, what is t
erica [24]

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10s

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7 0
3 years ago
Un automovil con la velocidad de 5 m/s acelera durante 12 s a 3 m/s2,¿cual es la velocis
harina [27]

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60 miles

Explanation:

4 0
2 years ago
Heat in the amount of 100 kJ is transferred directly from a hot reservoir at 1320 K to a cold reservoir at 600 K. Calculate the
Zinaida [17]

Answer:0.0909 kJ/K

Explanation:

Given

Temperature of hot Reservoir T_h=1320 K

Temperature of cold Reservoir T_l=600 K

Heat of 100 kJ is transferred form hot reservoir to cold reservoir

Hot Reservoir is Rejecting heat therefore Q_1=-100 kJ

Heat is added to Reservoir therefore Q_2=100 kJ

Entropy change for system

\Delta s=\frac{Q_1}{T_1}+\frac{Q_2}{T_2}

\Delta s=\frac{-100}{1320}+\frac{100}{600}

\Delta s=-0.0757+0.1666=0.0909 kJ/K

As entropy change is Positive therefore entropy Principle is satisfied

         

4 0
3 years ago
Many counties in Florida missed many school days in the fall of 2004 due to hurricanes that year. A solution for how to make up
Ivenika [448]

Answer:

108 extended days

Explanation:

Regular school hours a day = 6 hr

No. of school days to make up by extending the  regular hours = 3 days

Amount of time added to the regular hours of school = 10 min

No. of extended school days to make up the 3 school days by following the above mentioned criteria be x.

Time of school hours in 3 days = 3\times 6= 18\,hr\,\,\,\, ;or\,\,\, (18\times 60)\,minutes

\therefore x=\frac{18\times 60}{10}

x=108\,\,days are required to make up 3 days of school having 6 hours of regular timing with 10 minutes of add-on time each day.

4 0
3 years ago
If a car can go from 0 to 60 km/h in 8.0 seconds, what would be its final speed after 5.0 seconds if its starting speed were 50
dmitriy555 [2]

Answer:

This question assumes that the car accelerates at the same rate as when it went from 0 to 60km/h

24.29m/s or 87.4km/h

Explanation:

Let's find the acceleration of the car:

let vi=0, vf=60km/h (16.67m/s), Δt = 8.0s

a = (vf-vi)/Δt

a = (16.67m/s-0)/8.0

a = 2.08m/s^2

Now we can use this acceleration to find vf in the second part:

50km/h is 13.89m/s

a = (vf-vi)Δt

vf = aΔt + vi

vf = 2.08m/s^2*5.0+13.89m/s

vf = 24.29m/s (87.4km/h)

3 0
2 years ago
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