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FrozenT [24]
3 years ago
15

Answer? Please make sure you answer it as a simplified fraction.

Mathematics
1 answer:
Tju [1.3M]3 years ago
8 0
<h3>Answers:  </h3><h3>a = 4</h3><h3>b = 11</h3><h3>The fraction is 4/11</h3>

==================================================

Work Shown:

Let x = 0.363636...

The "36" pattern goes on forever as indicated by the three dots.

Multiply both sides by 100 to get 100x = 36.363636...

Effectively, multiplying by 100 moves the decimal point over 2 spots to the right. The "36" goes on forever here too. The key is to match up the infinite sequences of "36"s and cancel them out through subtraction

36.363636... - 0.363636... = 36

while

100x - x = 99x

So after subtracting the equations, we end up with 99x = 36

From here we solve for x by dividing both sides by 99 and reducing the fraction

99x = 36

x = 36/99

x = (9*4)/(9*11)

x = 4/11

As a check, use your calculator to find that

4/11 = 0.36363636...

so the answer is confirmed

Note: your calculator may display something like 0.3636363636364, that 4 should not be there. It's a result of rounding (due to the next digit being a 6). Keep in mind that rounding error is often a possibility when it comes to approximate calculations. The calculator only has so much memory and display space.

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Step-by-step explanation:

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Step-by-step explanation:

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Suppose in the University of Manitoba, 40% of the students live in apartments. If 600 students are randomly selected, then the a
just olya [345]

Answer:

P(200\leq X\leq 400)=P(\frac{200-240}{12}\leq \frac{X-\mu}{\sigma}\leq \frac{400-240}{12})=P(-3.33\leq Z \leq 13.33)

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So then the correct answer would be:

B) .9996

Step-by-step explanation:

The exact way to solve this problem is using the binomial distribution, assuming that our random variable of interest is "number of students living in apartments" represented by X and X \sim Bin(n=600, p =0.4)

And we want this probability:

P(200 \leq X \leq 400) [tex]In order to find this probability we can use the foloowing excel code:"=BINOM.DIST(400,600,0.4,TRUE)-BINOM.DIST(199,600,0.4,TRUE)"And we got:[tex] P(200 \leq X \leq 400) =0.999675[tex]But for this case the problem says that we need to approximate, so then we can use the normal approximation to the normal distribution. We need to check the conditions in order to use the normal approximation.&#10;[tex]np=600*0.4=240\geq 10

n(1-p)=600*(1-0.4)=360 \geq 10

So we see that we satisfy the conditions and then we can apply the approximation.

If we appply the approximation the new mean and standard deviation are:

E(X)=np=600*0.4=240

\sigma=\sqrt{np(1-p)}=\sqrt{600*0.4(1-0.4)}=12

And then X \sim N (\mu = 240, \sigma= 12)

And we are interested on the following probability:

P(200\leq X\leq 400)=P(\frac{200-240}{12}\leq \frac{X-\mu}{\sigma}\leq \frac{400-240}{12})=P(-3.33\leq Z \leq 13.33)

=P(Z

So then the correct answer would be:

B) .9996

6 0
3 years ago
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