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Alex17521 [72]
3 years ago
13

What is the domain and range of the graph?

Mathematics
1 answer:
Andreas93 [3]3 years ago
8 0

Answer:

Domain= how many boxes there are from each circle to the other, and the range is basically the height. In this case, Domain= 8, Range=2

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Solve for x please help me
Mademuasel [1]

x = 51.98

Step-by-step explanation:

tan 68 = opp/hyp = x/21

or

x = 21×tan68°

= 21(2.475)

= 51.98

3 0
2 years ago
What are the slope and y-intercept of the graph of this equation?
schepotkina [342]

Answer:

slope = y = 1/2

y-intercept = b = -3

Step-by-step explanation:

slope intercept equation:

y = mx + b----->(equation 1)

m is slope

b is y-intercept

y = 1/2x - 3----->(equation 2)

Compare (equation 1) and (equation 1)

slope = y = 1/2

y-intercept = b = -3

3 0
2 years ago
7m -- 4 for m = 8<br> Evaluate the following algebraic expression
arsen [322]
I don’t understand the question
If you mean
7m-4
M=8, this is the solution
7(8)-4
56-4
=52
But if you mean
7m- - 4
As in - + - = +
Then this is your answer
7(8)+4
56+4
=60
7 0
2 years ago
What does it mean to eliminate a variable?
uranmaximum [27]

Answer:

The elimination method for solving systems of linear equations uses the addition property of equality. You can add the same value to each side of an equation.

So if you have a system: x – 6 = −6 and x + y = 8, you can add x + y to the left side of the first equation and add 8 to the right side of the equation. And since x + y = 8, you are adding the same value to each side of the first equation.

7 0
2 years ago
Which step is the same in the construction of parallel lines and the construction of a perpendicular line through a point on the
madam [21]

Answer:

D.Place the compass on a point on the original line.

Complete Question:

A.Create only one arc that intersects the original line.

B.Create two arcs that intersect the original line.

C.Place the compass on a point off the original line.

D.Place the compass on a point on the original line.

Step-by-step explanation:

* Lets revise the steps of constructing parallel lines and a perpendicular line through a point on the line

<em># Contracting parallel lines</em>

- Given: Line AB and point P not on AB

1. Draw a slant line through point P and intersects AB at point C, this line is the transversal of the parallel lines

2.<u> Place the pin of the compass at point C</u> and draw an arc intersects AB at D and CP at E

3. Without changing the distance of the compass put the pin of the compass on point P and draw an arc intersects CP at point Q

4. Use the compass to measure the distance from D to E and place the pin of the compass at point Q and draw an arc intersects the arc from P to CP at point U

5. Join P and U by a line this line is parallel to AB

<em># Constructing a perpendicular line through a point on the line</em>

- Given line AB and point P lies on it

1. <u>Place your compass pin at P </u>and draw an arc of any size below AB that crosses the line twice at points C and D

2. Stretch the compass to a larger distance

3.<u> </u>Place the compass pin on point C<u> </u>and draw a small arc above the line

4. Without changing the distance of the compass place the compass pin on point D and draw another arc intersects the arc from C at point E

5. Using a straightedge, join P and E where PE is perpendicular to AB

*<em> Lets find the same steps in the constructions</em>

∵ In first construction we put the pin of the compass at point C which  lies in the original line AB

∵ In second construction we put the pin of the compass at point P which lies in the original line AB

∴ The common step is:  <em><u>"Place the compass on a point on the original line"</u></em>

6 0
3 years ago
Read 2 more answers
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