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Alex17521 [72]
2 years ago
13

What is the domain and range of the graph?

Mathematics
1 answer:
Andreas93 [3]2 years ago
8 0

Answer:

Domain= how many boxes there are from each circle to the other, and the range is basically the height. In this case, Domain= 8, Range=2

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Drag the tiles to the correct boxes to complete the pairs.Not all tiles will be used match the equations representing parabolas
IceJOKER [234]

Answer:

y=-8.08 -------> y+8=3(x+2)^{2}

y=14.25 -------> y-14=-(x-3)^{2}

y=-7.625 -----> y+7.5=2(x+2.5)^{2}

y=17.25 -------> y-17=-(x-3)^{2}

y=-7.25 -------> y+7=(x-4)^{2}

y=6.25 -------> y-6=-(x-1)^{2}

Step-by-step explanation:  

we know that

The standard form of a vertical parabola is equal to

(x-h)^{2}=4p(y- k)

where

(h,k) is the vertex

the focus is (h, k + p)

and

the directrix is y = k - p

Part 1) we have

y+8=3(x+2)^{2}

Convert to standard form

(x+2)^{2}=(1/3)(y+8)

The vertex is the point (-2,-8)

h=-2,k=-8

4p=1/3

p=1/12

the directrix is equal to

y = k-p -----> y=-8-(1/12)=-8.08

Part 2) we have

y-14=-(x-3)^{2}

Convert to standard form

(x-3)^{2}=-(y-14)

The vertex is the point (3,14)

h=3,k=14

4p=-1

p=-1/4

the directrix is equal to

y = k-p -----> y = 14-(-1/4)=14.25

Part 3) we have

y+7.5=2(x+2.5)^{2}

Convert to standard form

(x+2.5)^{2}=(1/2)(y+7.5)

The vertex is the point (-2.5,-7.5)

h=-2.5,k=-7.5

4p=1/2

p=1/8

the directrix is equal to

y = k-p -----> y=-7.5-(1/8)=-7.625

Part 4) we have

y-17=-(x-3)^{2}

Convert to standard form

(x-3)^{2}=-(y-17)

The vertex is the point (3,17)

h=3,k=17

4p=-1

p=-1/4

the directrix is equal to

y = k-p -----> y = 17-(-1/4)=17.25

Part 5) we have

y+7=(x-4)^{2}

Convert to standard form

(x-4)^{2}=(y+7)

The vertex is the point (4,-7)

h=4,k=-7

4p=1

p=1/4

the directrix is equal to

y = k-p -----> y=-7-(1/4)=-7.25

Part 6) we have

y-6=-(x-1)^{2}

Convert to standard form

(x-1)^{2}=-(y-6)

The vertex is the point (1,6)

h=1,k=6

4p=-1

p=-1/4

the directrix is equal to

y = k-p -----> y=6-(-1/4)=6.25

4 0
2 years ago
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