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3 years ago

Explain how you know that x^2-8x+20 is always positive. Please help.

Mathematics

1 answer:

IRISSAK [1]3 years ago

4 0

Answer:

if you rearrange to complete the square, you get (x^2-4)^2 +4

and seeing as anything squared will always be positive or zero, the lowest possible value for (x^2-4)^2 is 0, when x = 4

and 0 + 4 = 4, which is greater than 0, so positive

Step-by-step explanation:

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Evaluate the expression when g = 6 and h=34.<br>h-5g

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Use the distributive property to simplify the expression 3(y + 9).

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Answer:

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Which are the solutions of x2 = –11x + 4?

Zarrin [17]

For this case we have the following polynomial:

$x ^ 2 = -11x + 4$

Rewriting the polynomial we have:

$x ^ 2 + 11x - 4 = 0$

From here, we can solve the polynomial using the quadratic equation

We have then:

$x=\frac{-b+/-\sqrt{b^2-4ac}}{2a}$

$x=\frac{-11+/-\sqrt{11^2-4(1)(-4)}}{2(1)}$

$x=\frac{-11+/-\sqrt{11^2+16}}{2}$

$x=\frac{-11+/-\sqrt{121+16}}{2}$

$x=\frac{-11+/-\sqrt{137}}{2}$

Therefore, the solutions are:

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$x=\frac{-11-\sqrt{137}}{2}$

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