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xxMikexx [17]
3 years ago
10

When atoms bond with each other, they exchange A.) Protons B) Neutrons C)Electrons

Physics
1 answer:
schepotkina [342]3 years ago
6 0
C)Electrons................................
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An object with a mass of 7.60 kg is moving to the right and experiences an applied force of 50 N to the right. The friction forc
horrorfan [7]

Answer:

Explanation:

We will use the equation F - f = ma, which is a fancy way of stating Newton's 2nd Law.

F = +50.0,

f = -30.0,

m = 7.60 kg. Therefore:

50.0 - 30.0 = 7.60a and

20.0 = 7.60a and

a = 20.0/7.60 so

a = 2.63 m/s/s to the right

4 0
3 years ago
A 8.0 cm-diameter horizontal pipe gradually narrows to 4.5 cm. When water flows through this pipe at a certain rate, the gauge p
Fed [463]

Answer:

7.11x10^-3

Explanation:

We are to get the volume rate of flows

1/2pv1² + pl = 1/2pv2²

Such that A1V1 = A2V2

V1 = A2V2/A1

From the attachment I uploaded, we have a formula named equation 1 from which I have plugged in these values

P2 = 33000

P2 = 24000

P = 1000

r2 = 2.25

r1 = 4

When we put these values into the equation,

V2 = 4.47

A2V2 = pi(0.0225)²x4.47

= 7.7x19^-3m³/s

6 0
3 years ago
What is the fault-current circuit breaker? Describe its function.
Nimfa-mama [501]

Answer:

A circuit breaker is a switching mechanism that interrupts the current that is irregular or fault. It is a mechanical system that interferes with high magnitude (fault) current flow and also performs a transfer operation. Hope this helps :)

Explanation:

4 0
3 years ago
Read 2 more answers
An object of mass 8kg is attached to massless string of length 2m and swum with a tangential velocity of 3 what is the tension o
Paul [167]

Answer:

36 N

Explanation:

If the object of mass, m = 8 kg is swung in a horizontal circle of radius, r = 2m = length of string with tangential velocity v = 3 m/s, the tension in the string is the centripetal force which is T = mv²/r

= 8 kg × (3 m/s)²/2 m

= 4 kg × 9 m/s²

= 36 N

6 0
3 years ago
A graduated beaker with 375 mL of water is sitting on a scale which measures the weight of the glass and water to be 7.60 N. Whe
Allisa [31]

Answer:

Volume of water displaced = 450 - 375 = 75 ml

Vr = volume of rock = 75 ml

Wr = 9.22 - 7.60 = 1.62 N  weight of 75 ml of rock

Density of rock = 1.62 N / 75 ml = .0216 N / ml

Density of water = 1000 g / 1000 ml = 9.8 N / 1000 ml = .0098 N / ml

Density of rock / density of water = .0216 / .0098 = 2.20

8 0
3 years ago
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