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DiKsa [7]
3 years ago
14

Which type of thermal energy transfer does a wrapping of cotton or plastic reduce the most, conduction, convection, radiation, t

ranslation
Physics
1 answer:
Veseljchak [2.6K]3 years ago
8 0

Answer: Thermal Energy is energy resulting from the motion of particles; It is a form of kinetic energy and is transferred as heat; Thermal Energy Transfer can occur by three methods: Conduction; Convection; Radiation; Conduction. Conduction is the transfer of thermal energy through direct contact between . particles of a substance.

Explanation:

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Who are the scientists given credit for discovering electrons, protons, and neutrons?
nydimaria [60]
J.J. Thompson is the scientist who recieved credit for discovering them.
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Liquid water heats up and cools down slowly. What causes this property?
Alja [10]

Answer:

water forms hydrogen bonds

Explanation:

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Multiple-Concept Example 7 and Interactive LearningWare 26.1 provide some helpful background for this problem. The drawing shows
Vlada [557]

Answer:

n = 1.4266

Explanation:

Given that:

refractive index of crystalline slab n = 1.665

let refractive index of fluid is n.

angle of incidence θ₁ = 37.0°

Critical angle \theta _c = sin^{-1} (\frac{n}{n_{slab}} )

sin \theta _ c =\frac{n}{n_{slab}}

According to Snell's law of refraction:

n sin \theta _1 = n_{slab}  \ sin \  (90- \theta_c)

At point P ; 90 - \theta _2  \leq \theta _c

\theta _2 = 90 - \theta _c

Therefore:

n \ sin \theta_1 = n_{slab} \sqrt{(1-sin^2 \theta _c)}  \\ \\ n \ sin \theta_1 = n_{slab}   \sqrt{(1- \frac{n}{n_{slab}} )}

Then maximum value of refractive index  n of the fluid is:

n = \frac{n_{slab}}{\sqrt{1+ sin^2 \theta _1 } }

n = \frac{1.665}{\sqrt{1+ sin^2 \  37} }

n = 1.4266

3 0
2 years ago
!!!!!!PLEASE HELP ASAP !!!!!!!!!!!!
OLga [1]

Answer: d constint speed

Explanation: im 15 and no the answer

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2 years ago
Multiple-Concept Example 6 reviews the concepts that play a role in this problem. A diver springs upward with an initial speed o
adell [148]

Answer:

Part a)

v_f = 7.99 m/s

Part b)

y = 3.25 m

Explanation:

Part a)

Since the diver is moving under gravity

so here its acceleration due to gravity will be uniform throughout the motion

so here we will have

v_f^2 - v_i^2 = 2 a y

here we have

v_i = 2.22 m/s

y = -3 m

v_f^2 - (2.22)^2 = 2(-9.81)(-3)

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Part b)

at highest point of his motion the final speed will be zero

so we will have

v_f^2 - v_i^2 = 2 a (\Delta y)

0 - 2.22^2 = 2(-9.81)(y - 3)

y = 3.25 m

7 0
3 years ago
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