Greatest common factor (or denominator) is 6,
least common multiple is 180
hmm
(note:
I spent like 30 mins trying to use a math only of finding the values
but it didn't work so I did a force brute and elimination method
explained below)
so
a and b must be multiples of 6
so list all the multiples of 6
wait
180=6*30
and 30's factors are 1,2,3,5,6,10,15,30 so only list the numbers that
are the result of multiplying 6 and any of those numbers in that list
(so we can have the lcm of 180)
so
6*1=6
6*2=12
6*3=18
6*5=30
6*6=36
6*10=60
6*15=90
6*30=180
these are our possible candidates for the 2 numbers
now we must find the pair that has a GCD of only 6
doing the math is long and tedious so do it yourself (trial and error)
we see that our choices that fulfill both requirements (GCD of 6 and LCM of 180) are
90&12
60&18
30&36
sum them to find the least one
90+12=102
60+18=78
30+36=66
the least possible sum is 66
Sqrt 13 and 1.1919919991... are irrational, meaning that they can't be described in a fraction of one integer over another, like 1/3, 45/44 or 57/107, these numbers are rational. Most irrationals are known constants like e or π, endless non-repeating decimals, or roots of non-perfect numbers like 13, 7, 5 or 2.
If the answer is an equation then it is:
x=(4y+15)/(5-3y)
Answer:
13.75$
Step-by-step explanation:
First, take 10% of 12.50$. That will give you 1.25$.
Next, add that to 12.50$ to get your new hourly pay.
Answer:
15
Step-by-step explanation:
For these kind of problems, its best to use a Venn Diagram.
Lets break down the information:
<em>There are 50 students total.</em>
<em>25 take Math competiton classes.</em>
<em>29 take Geometry</em>
<em>12 take history and </em><em><u>no math classes</u></em>
<em>19 take </em><em><u>both math classes</u></em>
Now, make a Venn Diagram.
[Look at the photo attached. Also, the blank spaces in the Venn Diagram are ones that no student takes.]
The 12 taking history and no math classes and 3 kids not taking any of those classes look like they're the only ones not taking either math class.
12 + 3 = 15.
So the answer is 15.
[I'm not sure if this is correct or if I made a mistake so please let me know! Thank you! I hope this helps!]
:)