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rewona [7]
4 years ago
14

A segment of DNA that codes for the ability to make one type of protein molecule is known as what ?

Chemistry
1 answer:
ahrayia [7]4 years ago
7 0
The answer is a gene
You might be interested in
Hydrogen gas and oxygen gas combine according to this reaction: 2H2(g]+O2(g]→2H2O(l]At STP, a chemist mixes 3.74 L of hydrogen g
zavuch27 [327]

Answer:

1.47 Liters of O₂ were reacted

Explanation:

The reaction is:

2H₂ (g) + O₂(g) → 2H₂O(l)

As we have the volume of hydrogen we need to work with denstiy to determine the moles that have reacted.

Density = mass / volume

Density . volume = mass → 0.071 g/L . 3.74L = 0.265 g

We determine the moles of H₂ → 0.265 g. 1mol/2g = 0.132 moles

In the reaction, ratio is 2:1. We make a rule of three:

2 moles of H₂ need 1 mol of O₂ to react

Then, 0.132 moles would need (0.132 .1)/2 = 0.066 moles of O₂

In order to determine the volume we need the oxygen's density but, we have to convert the mass to moles, firstly.

0.066 moles . 32 g/ 1mol = 2.12 g

Then oxygen's density = oxygen's mass / oxygen's volume

Oxygen's volume = oxygen's mass / oxygen's density

O₂ volume = 2.12 g / 1.43 g/L = 1.47 L

5 0
3 years ago
Read 2 more answers
The enthalpy of formation of CO2 at 25oC is -393.51 kJ/mol. What is the enthalpy of formation at 500 oC?
Kisachek [45]

Answer:

-375.9_KJ/(mol)

Explanation:

H(T2 ) ≈ H(T1)+CPΔT

Specific heat of Carbon is 0.71 J/g K.

At 283.15 the heat capacity is 37.12 J/(mol*K)

Kirchhoff's law

H(T2 ) ≈ H(T1)+CPΔT

Where

H(T1) and H(T2 ) are the heat of formation of CO2 at temperatures T1 and T2

CP is the heat capacity

Thus we have and ΔT is the temperature change

H(T2 ) ≈ -393.51×10^3+CP×(500-25)

= -393.51×10^3+37.12×(500-25)

= -375878 J/(mol)

= -375.9KJ/(mol)

6 0
3 years ago
De, it
allsm [11]

If u click on all of them it gives u an A+ and doesn’t even read what u wrote. So u never really have to try hard on the writing parts just tell them u included them all

4 0
3 years ago
The above reaction is run and found to follow second order kinetics with a rate constant of 1.30 x 10-3 M-1sec-1. If the initial
Leya [2.2K]

The final concentration after 172 seconds is 1.15 M. To obtain this answer, use the the integrated rate law for the order of reaction. Based on the problem, this is a second order reaction. The units of the rate constant also support that it is a second order reaction.

Further Explanation:

The solution to this problem is straightforward.

  1. Identify the integrated rate law for the corresponding order of reaction.
  2. Substitute the given values into the integrated rate law equation.
  3. Use algebra to solve for the unknown, C(f).

STEP 1: Since the reaction is a second order reaction, the integrated rate law will be:

\frac{1}{C_{f}} = \ kt \ + \frac{1}{C_{i}}

where:

C(f) is the final concentration

k is the rate constant

t is the time

C(i) is the initial concentration

STEP 2: Plugging in the values given in the problem into the equation, the following equation should be obtained:

\frac{1}{C_{f}} \ = (1.30  \ x \ 10^{-3} \frac{ \ 1 }{ \ M-s})(172 \ s) \ + \ \frac{1}{1.54 \ M} \\

STEP 3: Using algebra to solve for C(f):

\frac{1}{C_{f}} = \ 0.87295\\ \\C_{f} = \ 1.14554 \ M

Since the given values only have 3 significant figures, the final answer must be expressed with 3 significant figures as well.

Therefore,

\boxed {C_{f}\ =  \ 1.15 \ M}

Learn More

  1. Learn more about half life brainly.com/question/4318844
  2. Learn more about first order reaction brainly.com/question/8139015
  3. Learn more about rate law brainly.com/question/1450796

Keywords: rate law, second order, integrated rate law

3 0
3 years ago
how many molecules, elements, and total atoms are present in the following chemical formula? Mg(NO3)2
Scrat [10]
1 molecule. the coefficient tells you that and since there isn't one then it's 1 molecule.
There is 3 elements. Mg= 1 atom N=2 atoms O=6 atoms. The total number of atoms is 9.

To put it simple
1 molecule
3 elements
9 atoms
8 0
4 years ago
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