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Answer:
392 g
Explanation:
The given concentration tells us that<em> in 100 g of solution, there would be 15.3 g of 2-ethyltoluene</em>.
With that in mind we can<u> calculate how many grams of solution would contain 60.0 g of 2-ethyltoluene</u>:
- Mass of solution * 15.3 / 100 = 60.0 g 2-ethyltoluene
Answer : The correct option is, (C) 1.7
Explanation :
First we have to calculate the moles of
and
.


The balanced chemical reaction will be:

0.01 mole of
dissociate to give 0.01 mole of
ion and 0.02 mole of
ion
and
0.03 mole of
dissociate to give 0.03 mole of
ion and 0.03 mole of
ion
That means,
0.02 moles of
ion neutralize by 0.02 moles of
ion.
The excess moles of
ion = 0.03 - 0.02 = 0.01 mole
Total volume of solution = 100 + 300 = 400 ml = 0.4 L
Now we have to calculate the concentration of
ion.


Now we have to calculate the pH of the solution.
![pH=-\log [H^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%20%5BH%5E%2B%5D)


Therefore, the pH of the solution is, 1.7
Answer:
the molar mass for fluorine is 37.99681 g/mol