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IrinaK [193]
2 years ago
7

Who discovered electrons

Chemistry
2 answers:
mart [117]2 years ago
6 0

during tbe 1880s and 90s scientist searched cathode rays for the carrier of the electrical properties in matter. the person who discovered Thomson of the electron of 1897.

natulia [17]2 years ago
5 0
J.j. Thomson discovered them
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You are on vacation with your family up in the mountains. Your friend is on vacation near the equator by the ocean. Explain whic
Kay [80]

Answer:

it would be colder on the mountains becouse there is less air up there and it would be a lot more humid down by the ocean

Explanation:

3 0
2 years ago
Identify the compound in the following group that is most soluble in water. Match the words in the left column to the appropriat
gogolik [260]

Answer:

Following are the responses to the given points:

Explanation:

For question 1:

Butanoic acid, butane, and butanone are also the three chemicals most dissolve in water. Its intermolecular force forces are produced by carboxylic acid functional groups with water.

For question 2:

Butanoic acid is a rancid buffer.

Methanoic acid is responsible for the stinging red ants

For question 3:

Methyl butanoate's chemical structure.

8 0
3 years ago
What does a net ionic equation show about a reaction
AVprozaik [17]

Answer:

A net ionic equation shows only the chemical species that are involved in a reaction, while a complete ionic equation also includes the spectator ions.

Brainlist pls!

6 0
3 years ago
The solubility of calcium sulfate at 30°c is 0.209 g/100 ml solution. calculate its ksp.
inessss [21]
Answer is: Ksp for calcium sulfate is 2.36·10⁻⁴.
Balanced chemical reaction (dissociation):
CaSO₄(s) → Ba²⁺(aq) + SO₄²⁻(aq).
m(CaSO₄) = 0.209 g.
n(CaSO₄) = m(CaSO₄) ÷ M(CaSO₄).
n(CaSO₄) = 0.209 g ÷ 136.14 g/mol.
n(CaSO₄) = 0.00153 mol.
s(CaSO₄) = n(CaSO₄) ÷ V(CaSO₄).
s(CaSO₄) = 0.00153 mol ÷ 0.1 L = 0.0153 M.
Ksp = [Ca²⁺] · [SO₄²⁻].
[Ca²⁺] = [SO₄²⁻] = s(CaSO₄).
Ksp = (0.0153 M)² = 2.36·10⁻⁴.
8 0
2 years ago
A 6.50x10^-5 m solution of potassium permanganate has a percent transmittance of 27.3% when measured in a 1.15 cm cell at a wave
mihalych1998 [28]
For this problem, we use the Beer Lambert's Law. Its usual equation is:

A = ∈LC
where
A is the absorbance
∈ is the molar absorptivity
L is the path length
C is the concentration of the sample solution

As you notice, we only have to find the absorbance. But since we are not given with the molar absorptivity, we will have to use the modified equation that relates % transmittance to absorbance:

A = 2 - log(%T)
A = 2 - log(27.3)
A = 0.5638
7 0
2 years ago
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