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Katen [24]
2 years ago
5

If the pH of a solution is 5.6, what is the pOH?

Chemistry
1 answer:
Nataly_w [17]2 years ago
7 0

Answer:

pOH= 8.4

Explanation:

pH+pOH=14

5.6+pOH= 14

pOH= 14-5.6= 8.4

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3 years ago
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Answer:

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Explanation:

4 0
2 years ago
If the pH of vinegar is 3.0, what is the concentration of H+ in vinegar?
Cerrena [4.2K]

Answer: The concentration of H^{+} ions in vinegar is 0.001 M.

Explanation:

Given: pH = 3.0

pH is the negative logarithm of concentration of hydrogen ion.

The expression for pH is as follows.

pH = - log [H^{+}]

Substitute the value into above expression as follows.

pH = - log [H^{+}]\\3.0 = - log [H^{+}]\\conc. of H^{+} = antilog (- 3.0)\\= 0.001 M

Thus, we can conclude that the concentration of H^{+} ions in vinegar is 0.001 M.

5 0
2 years ago
Reaction of acetylene with silver nitrate​
MAVERICK [17]

Answer:

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Explanation:

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5 0
2 years ago
What would happen to the rate of a reaction with rate law rate = k [NO]^2[H2] if
Ede4ka [16]

The rate of a reaction would be one-fourth.

<h3>Further explanation</h3>

Given

Rate law-r₁ = k [NO]²[H2]

Required

The rate of a reaction

Solution

The reaction rate (v) shows the change in the concentration of the substance (changes in addition to concentrations for reaction products or changes in concentration reduction for reactants) per unit time.  

Can be formulated:  

Reaction: aA ---> bB  

\large{\boxed{\boxed{\bold{v~=~-\frac{\Delta A}{\Delta t}}}}

or  

\large{\boxed{\boxed{\bold{v~=~+\frac{\Delta B}{\Delta t}}}}

The concentration of NO were halved, so the rate :

\tt r_2=k[\dfrac{1}{2}No]^2[H_2]\\\\r_2=\dfrac{1}{4}k.[No]^2[H_2]\\\\r_2=\dfrac{1}{4}r_1

3 0
2 years ago
Read 2 more answers
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