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Katen [24]
2 years ago
5

If the pH of a solution is 5.6, what is the pOH?

Chemistry
1 answer:
Nataly_w [17]2 years ago
7 0

Answer:

pOH= 8.4

Explanation:

pH+pOH=14

5.6+pOH= 14

pOH= 14-5.6= 8.4

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3 0
2 years ago
For each value of the principal quantum number n, what are the possible values of the electron spin quantum number?
Ede4ka [16]

Answer:

The values for spin quantum number +1/2 and - 1/2

Explanation:

Principal quantum number denoted by (n) is used to describe the shell or orbits that electrons are found. Principal quantum number can assume a value of n= 1,2, 3, 4,5............ which indicates K, L, M, N, O shell respectively.

To know the maximum number of electrons in each shell, the formula (2n²) can be used. The letter 'n' denotes the values of principal quantum number 1,2,3,4

For example

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  • n=2 (L shell) has the maximum number of 8 electrons
  • n=3 (M shell) has the maximum number of 18 electrons
  • n=4 (N shell) has the maximum number of 32 electrons

All the electron in each shell will have a spin quantum number of +1/2 and - 1/2. One electron in each degenerate orbital will spin up (+1/2) while the other electron will spin down (-1/2).

7 0
3 years ago
¿Cuál es ion monoatomico más estable formado a partir de aluminio?
Naily [24]

Answer:

3+

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3 0
3 years ago
Read 2 more answers
The half-life of a first-order reaction is 13 min. If the initial concentration of reactant is 0.085 M, how long would it take u
olasank [31]

Answer: It will take 8.2 minutes until the concentration decreases to 0.055 M

Explanation:

The time after which 99.9% reactions gets completed is 40 minutes

Explanation:

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant

t = age of sample

a = let initial amount of the reactant

a - x = amount left after decay process  

a) for completion of half life:

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

t_{\frac{1}{2}}=\frac{0.693}{k}

k=\frac{0.693}{13min}=0.053min^{-1}

b)  Time taken for 0.085 M to decrease to 0.055 M

t=\frac{2.303}{0.053}\log\frac{0.085}{0.055}

t=8.2min

Thus it will take 8.2 minutes until the concentration decreases to 0.055 M

5 0
3 years ago
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