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saw5 [17]
3 years ago
9

BRAINLIESTTT ASAP!! PLEASE HELP ME :))

Chemistry
1 answer:
VLD [36.1K]3 years ago
7 0

Answer:

A - thinking of various research topics

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Based on the wildfires that are occurring along the west coast in Washington,
aniked [119]

Answer:

Yes, wind and temperature are responsible for the spreading of fire.

Explanation:

Chemistry play a key role in the chemical reaction that is occurring in the wildfires because chemistry is the study of chemicals and in wildfires, the reaction of chemicals is responsible for the occurring and spreading of fire. Yes, wind currents and temperature has a great influence  on the fire spreading in the forests. The fire occurs in the forest is due to temperature while its spreading happens due to wind. Placing water on the fire does not help extinguish the fire because the the fire particles can be transmitted for a fair distance by wind.

4 0
4 years ago
If you start with 6 moles of N2 and 6 moles of H2 (meaning you won't have enough of 1 of the ingredients), how many moles of NH3
Ivahew [28]

Answer:

4molNH_3

Explanation:

Hello there!

In this case, according to the given information it will be firstly necessary to set up the chemical equation taking place:

N_2+3H_3\rightarrow 2NH_3

We infer we need to calculate the moles of NH3 by using both of the moles of N2 and H2 at the beginning, in order to identify the limiting reactant:

n_{NH_3}=6molN_2*\frac{2molNH_3}{1molN_2}=12molNH_3\\\\ n_{NH_3}=6molH_2*\frac{2molNH_3}{3molH_2}=4molNH_3\\

Thus, since hydrogen yields the fewest moles of ammonia, we conclude that we are just able to yield 4 moles of NH3.

Regards!

8 0
3 years ago
What are the characteristics of temperature ​
solong [7]
Humidity, air temperature and pressure, wind speed and direction, cloud cover and type, and the amount and form of precipitation are all atmospheric characteristics of the momentary conditions we call weather. ... Differential warming, in turn, causes variations in the temperature and pressure of overlying air masses.
4 0
3 years ago
Calculate the frequency (Hz) and wavelength (nm)
sergey [27]

Answer:

wavelength, λ =  486.6 nm

frequency, f = 6.16 * 10¹⁴ Hz

Explanation:

a. Wavelength

Using the wavelength equation; 1/λ = (1/hc) * 2.18 * 10⁻¹⁸ J * (1/nf² - 1/ni²)

Where nf is the final energy level; ni is the initial energy level; h is Planck's constant = 6.63 * 10⁻³⁴ J.s; c is velocity of light = 3 * 10⁸ m/s

1/λ = 1/(6.63 * 10⁻³⁴ J.s * 3 * 10⁸ m/s) * 2.18 * 10⁻¹⁸ J * (1/2² - 1/4²)

1/λ = 2.055 * 10⁶ m

λ = 4.866 * 10⁻⁷ m

wavelength, λ =  486.6 nm

b.  Frequency

Using f = c/λ

f = (3 * 10⁸ m/s) / 4.866 * 10⁻⁷ m

frequency, f = 6.16 * 10¹⁴ Hz

7 0
3 years ago
What is the frequency of a photon of light (in Hz) that has an energy of 2.50 x 10-18 J?
ohaa [14]

Answer:

The answer is

3.77 \times  {10}^{15}  \:  \:  \: Hz

Explanation:

The frequency of the photon can be found by using the formula

f =  \frac{E}{h}  \\

where

E is the energy

f is the frequency

h is the Planck's constant which is

6.626 × 10-³⁴ Js

From the question

E = 2.50 × 10^-18 J

So we have

f =  \frac{2.50 \times  {10}^{ - 18} }{6.626 \times  {10}^{ - 34} }  \\

We have the final answer as

3.77 \times  {10}^{15}  \:  \:  \: Hz

Hope this helps you

5 0
3 years ago
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