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saw5 [17]
3 years ago
9

BRAINLIESTTT ASAP!! PLEASE HELP ME :))

Chemistry
1 answer:
VLD [36.1K]3 years ago
7 0

Answer:

A - thinking of various research topics

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2000 minutes to hours dimensional analysis
elena-14-01-66 [18.8K]

Answer:

33.33 h

Explanation:

You know that

1 h = 60 min

If you divide both sides by 60 min, you get the conversion factor: 1 h/60 min = 1.

If you divide both sides by 1 h, you get the conversion factor: 1 = 60 min/1 h.

Both are conversion factors because they both equal one and multiplying a measurement by one does not change its value.

You choose the conversion factor that gives you the correct dimensions for your answer. It must have the correct dimensions on top (in the numerator),

Thus, to convert 2000 min to hours, you use the conversion factor with “h” on the top.

\text{Time} = \text{2000 min} \times \dfrac{\text{1 h}}{\text{60 min}} = \textbf{33.33 h}

5 0
3 years ago
In the following reaction, when a surplus of hydrazine (N2H4) reacts with 20 liters of hydrogen peroxide (H2O2), how many liters
Ghella [55]
The answer is 10 liters.
5 0
3 years ago
Read 2 more answers
5) How many Kilograms are in 12 L of Chlorine Gas?
melamori03 [73]

Answer: 0.03798 kilograms

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given volume}}{\text {Molar Volume}}=\frac{12L}{22.4L}=0.535moles

1 mole of chlorine gas (Cl_2) weighs = 71 g

Thus 0.535 moles of chlorine gas (Cl_2) will weigh = \frac{71}{1}\times 0.535=37.98g=0.03798kg            (1kg=1000g)

Thus there are 0.03798 kilograms in 12 L of chlorine gas.

3 0
3 years ago
PLEASE I NEED THIS ANSWERED ASAP
kherson [118]
The answer would be: 
A. Cancel out CO because it appears as a reactant in one intermediate reaction and a product in the other intermediate reaction.

In this question, there are two half-reaction equations. To merge them up, you need to add the reactant with the reactant, then the product with the product. If there is a molecule on both side, you can cancel them. The full reaction would be:

C+ 1/2 O2 + CO + 1/2O2 ==>CO+ CO2       -----> remove CO from both side
C+ O2 ==>CO2
7 0
4 years ago
Please helpp!!! due todayyyy<br> Answer the 4 questions
timofeeve [1]
Where are the questions ?
5 0
3 years ago
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