Why does the dime transfer less momentum?
1 answer:
Answer:
This because the mass of the dime is very less = 2.268 grams only
Explanation:
Momentum :<em><u> It is product of mass and velocity of the objec</u></em>t.The affect of momentum can be observed by the force exerted <em><u>. Greater the change in momentum, greater the force exerted by the object</u></em>.
The formula of momentum(p) is :
Momentum depends upon :
1. Mass = Greater the mass of the object , greater the momentum . For example : you get more hurt by a heavy stone then a light ball when both hit you with the same velocity.
2. Velocity = Momentum of the object with more velocity is more. This application is used by the cricketers. While catching the ball , the fielder pushes his hand away. By doing this he decreases the velocity of the object. Hence the momentum decrease and the ball comes to catcher's hand easily.
The mass of dime = 2.26 gram So it has less momentum because of less mass.
Hence the force exerted or the momentum transferred by the Dime is very low .
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Answer:
-100 kJ
Explanation:
We can solve this problem by applying the first law of thermodynamics, which states that:
where:
is the change in internal energy of a system
Q is the heat absorbed/released by the system (it is positive if absorbed by the system, negative if released by the system)
W is the work done by the system (it is positive if done by the system, negative if done on the system)
For the system in this problem we have:
W = +147 kJ is the work done by the system
Q = +47 kJ is the heat absorbed by the system
So , its change in internal energy is:
Answer:
Explanation:
Hello,
In this case, we use the Avogadro's number to compute the molecules of C2F4 whose molar mass is 100 g/mol contained in a 485-kg sample as shown below:
Best regards,