Answer:
P = 57°
Step-by-step explanation:
Given the following :
PQ = 17
QR = 15
PR = 14
Using the cosine formula since the length of the three sides are given:
a2 = b2 + c2 – 2bccos(A)
To find P:
QR^2 = PQ^2 + PR^2 – 2(PQ)(PR)cos(P)
15^2 = 17^2 + 14^2 – 2(17)(14)cos(P)
225 = 289 + 196 - 476 cosP
476*CosP = 485 - 225
476*CosP = 260
CosP = 260/476
CosP = 0.5462184
P = Cos^-1(0.5462184)
P = 56.892029
P = 57°
Step-by-step explanation:
Given :
A bike path is 3 miles long. there are distance markers every path one fourth mile to the end of the path.
To Find :
Which number line correctly models this situation and the total number of distance markers.
Solution :
It is given that their are markers every 1/4 part of mile.
So, their are 4 markers per mile.
Numbers of markers in 3 miles long path is :
Therefore, the total number of distance markers in 3 mile path is 12.
Hence, this is the required solution.