Answer:
Yes,they are congruent.
Step-by-step explanation:
We are required to make two transformations and prove that they are congruent.
First Transformation:Now rotate the polygon FGHIJ by 90° about the axis parallel to x-axis and passinfg through the vertex I.You can observe that the sides are of same length AB=GF=2 units.
Second Transformation: Keeping the polygon ABCDE constant shift the centre of polygon FGHIJ to the centre of polygon ABCDE you will observe thta they exactly overlap on each other hence they are congruent with each other.
The distance formula is given by

Take point A(0, -7) as (x₁, x₂) and point B(8, 8) as (y₁, y₂)
Distance AB =

Distance AB =

Distance AB =

Distance AB = 17
The line AB is dilated to A'B' by scale factor of 2, it means the length of the line is multiplied by 2
Distance A'B' = 2 × 17 = 34 units
4x - y = 5 --> 4x = y + 5
substitute
4x + 4y = -4
(y + 5) + 4y = -4
5y + 5 = -4
5y = -9
y = -1.8
solve x
4x = y + 5 = -1.8 + 5 = 3.2
x = 3.2/4 = 0.8
NICKI IS THE QUEEN OF RAPPP
The general equation for a circle with center (a,b) and squared radius k is

Here we have

and the constant is fixed by substituting in the point we know (x,y)=(3,-5)

Answer:
