This is essentially 16/3 as a improper fraction. Then multiplied by 4/1 would be 64/3 which is 21.3 or 21 3/10
Answer:
No positive value of n
Step-by-step explanation:
we have to find out for how many positive values of n are both
our-digit integers
Let us consider first cube
we get 4digit lowest number is 1000 and it has cube root as 10.
Thus 10 is the least integer which satisfies four digits for cube.
The highest integer is 9999 and it has cube root as 21.54
or 21 the highest integer.
Considering 3^n we get,
3^10 is having 5 digits and also 3^21
Thus there is no positive value of n which satisfy that both n cube and 3 power n are four digits.
Total money needed = $14,000
Total money collected = $5358+$2834+4132 = $12324
Additional money needed = Total money - Money collected
=> $14,000 - $12,324
=> $1,676
So they need $1676 more money to be collected
Answer:
Let f(x) = x^3 -6x^2 +11x-8+K
by factor theorem, f(3)=0
27-54+33-8+K=0
K=2
hope that helps?
Step-by-step explanation: