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Mila [183]
3 years ago
7

Find the value of x . PLEASE HELP )):

Mathematics
1 answer:
Scorpion4ik [409]3 years ago
5 0

Answer:

x=65

Step-by-step explanation:

since its 65 on one side, its going to be 65 on the other. they are congurent

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Jalen bought 4 bottles of water, 2 bags of cashews, and a fruit salad. The cost of the fruit salad was $5. This expression was u
butalik [34]
The statment is correct but if you have to work out the value of x you need a total amount of the purchase without that or atleast some sort of value it is not possible to work out
3 0
3 years ago
When a jar of fruit is 2/3 of the way full it can hold 2 1/4 cups of fruit what fraction of the jar is full when it only contain
Natali [406]

Answer:

8/27

Step-by-step explanation:

<h2><u>Fractions</u></h2>

a jar of fruit is 2/3 of the way full it can hold 2 1/4 cups of fruit

what fraction of the jar is full when it only contains one cup of fruit?

by using these statements , we can solve this through <u>cross multiplication</u>:

fraction that the jar is full                   :           number of cups of fruit

                 \frac{2}{3}                                         :                        2 \frac{1}{4}

                 x                                         :                        1

\frac{2}{3}  = 2 \frac{1}{4} x

convert 2 \frac{1}{4} from a mixed fraction to an improper fraction

hence 2 1/4  = 9/4

solve

\frac{2}{3}  = \frac{9}{4} x.

x = \frac{2}{3} /  \frac{9}{4}

<u>x = 8/27</u>

<h3><u>when the cup contains one cup of fruit its fraction 8/27 full </u></h3>
5 0
3 years ago
Read 2 more answers
Solve each equation for the variable in red #11
Anna11 [10]
I can’t see the picture
6 0
3 years ago
( Algebra)plz can you do it?
Naya [18.7K]
I'm pretty sure the answer to this is x=65 but I could be wrong.Not very good with this kinda Algebra. 
6 0
3 years ago
Compute x/y if
Marysya12 [62]

Let first consider the equations one by one and will be solving one by one ;

{:\implies \quad \sf x+\dfrac{1}{y}=4}

Multiplying both sides by y will lead ;

{:\implies \quad \sf xy+1=4y}

{:\implies \quad \boxed{\sf xy=4y-1\quad \cdots \cdots(i)}}

Now, consider the second equation which is ;

{:\implies \quad \sf y+\dfrac{1}{x}=\dfrac14}

Multiplying both sides by x will yield

{:\implies \quad \sf xy+1=\dfrac{x}{4}}

{:\implies \quad \sf xy=\dfrac{x}{4}-1}

{:\implies \quad \boxed{\sf xy=\dfrac{x-4}{4}\quad \cdots \cdots(ii)}}

As LHS of both equations (i) and (ii) are same, so equating both will yield;

{:\implies \quad \sf 4y-1=\dfrac{x-4}{4}}

Multiplying both sides by 4 will yield

{:\implies \quad \sf 16y-4=x-4}

{:\implies \quad \sf 16y=x}

Dividing both sides by y will yield :

{:\implies \quad \boxed{\bf{\dfrac{x}{y}=16}}}

<em>Hence, the required answer is 16</em>

5 0
2 years ago
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