This is a Pythagorean theorem problem. the ladder is 12 from the building and needs to teach 14 ft up. the length of the ladder it's the hypotenuse
12²+14²=c²
144+196=c²
340=c²
c=√340 or about 18.5 ft
Answer:
6.552×10³×10
6.552×10^3+1
6.552×10^4 is the standard form
i hope this will help you :)
Answer/Step-by-step explanation:
Given:
m<EFH = (5x + 1)°
m<HFG = 62°
m<EFG = (18x + 11)°
Required:
1. Value of x
2. m<EFH
3. m<EFG
SOLUTION:
1. Value of x
m<EFH + m<HFG = m<EFG (angle addition postulate)
(5x + 1) + 62 = (18x + 11)
Solve for x using this equation
5x + 1 + 62 = 18x + 11
5x + 63 = 18x + 11
Subtract 18x from both sides
5x + 63 - 18x = 18x + 11 - 18x
-13x + 63 = 11
Subtract 63 from both sides
-13x + 63 - 63 = 11 - 63
-13x = -52
Divide both sides by -13
-13x/-13 = -52/-13
x = 4
2. m<EFH = 5x + 1
Plug in the value of x
m<EFH = 5(4) + 1 = 20 + 1 = 21°
3. m<EFG = 18x + 11
m<EFG = 18(4) + 11 = 72 + 11 = 83°
Answer:
If there isn't an exact number in the middle you take the two numbers that are in the "middle" add them together and divide by 2
Step-by-step explanation: