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bixtya [17]
3 years ago
10

What is the change in enthalpy for the following reaction? 

Chemistry
1 answer:
Tju [1.3M]3 years ago
7 0

The given chemical reaction is:

2H_{2}O_{2}(aq)---> 2H_{2}O(l)+O_{2}(g)

The standard heats of formation of H_{2}O and H_{2}O_{2} are:

ΔH_{f}^{0}(H_{2}O) = -285.8kJ/mol[/tex]

ΔH_{f}^{0}(H_{2}O_{2}) = -187.6 kJ/mol[/tex]

Calculating the change in heat:

ΔH^{0}_{reaction)=∑ΔH_{f}^{0}(products)-∑ΔH_{f}^{0}(reactants)

                         = [{2 * (-285.8 kJ/mol)} -{2*(-187.6 kJ/mol)}]

                          = -196.4 kJ/mol

Therefore, the change in enthalpy for the given reaction is -196.4 kJ/mol



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Answer:

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Equilibrium:               0.3 - 2x                 x

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         = -log 0.122

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