Answer:
6ΔG°(f) H₂O = -229 Kj/mol
Explanation:
4NH₃(g) + 5O₂(g) => 4NO(g) + 6H₂O(g)
ΔG°(f) 4mol(-16.66Kj/mol) | 5mol(0Kj/mol) || 4mol(+86.71Kj/mol) | 6ΔG°(f) H₂O
Hess's Law
ΔG°(Rxn) = ∑ΔG°(f) Products - ∑ΔG°(f) Reactants
-957.9 Kj = [(4mol(+86.71Kj/mol)) + 6ΔG°(f) H₂O(g)] - [4mol(-16.66Kj/mol) + 5mol(0Kj/mol)]
-957.9 Kj = [4(86.7)Kj + 6ΔG°(f) H₂O] - [4(-16.66)Kj] = 346.84Kj + 6ΔG°(f) H₂O + 66.64Kj
ΔG°(f) H₂O = ((-957.9 - 346.84 -66.64)/6)Kj = -228.56 Kj ≅ -228.6 Kj*
*Verified with Standard Heat of Formation Table
<span>H</span>₃<span>PO</span>₄<span> - Phosphoric Acid :
H</span>₃<span>PO</span>₄<span> = 1.0 * 3 + 31.0 + 16.0 * 4 = 98.0 g/mol
hope this helps!</span>
Answer:
the answer is a because thermal energy is heat and the question said that is not a factor of thermal energy so A does not refer to heat
the video say about the size of the container that you should use in pouring is as follows
Use small (compatible sized) containers when pouring. Larger containers can be more difficult to use and can cause spills.
chemistry lab equipment's
- Pipette Tips
- Cleaning Solutions and Hand Sanitizers
- Transfer Pipets
- Wipes
- Serological Pipets
- Gloves
- Centrifuge Tubes
Are the basic lab requirements
To learn more about chemistry lab equipment's
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