Chemical Digestion of Carbohydrates, Proteins, Lipids, and Nucleic Acids. The chemical breakdown of the macromolecules contained in food is completed by various enzymes produced in the digestive system.

5 0

3 years ago

an image of a statue appears to be 11.5cm behind convex mirror with focal length 13.5cm. Find the distance from the statue to th

professor190 [17]

Answer:

77.625 cm

Explanation:

The given distance of the image behind the convex mirror, v = 11.5 cm

The focal length of the mirror, f = 13.5 cm

The mirror formula for convex mirror is given as follows;

$\dfrac{1}{u} - \dfrac{1}{v} = -\dfrac{1}{f}$

Where;

u = The distance from the statue to the mirror

Therefore, we get;

$\dfrac{1}{u} = -\dfrac{1}{f} + \dfrac{1}{v}$

Plugging in the values gives;

$\dfrac{1}{u} = -\dfrac{1}{13.5} + \dfrac{1}{11.5} = \dfrac{8}{621}$

∴ The distance from the statue to the mirror, u = 621/8 cm = 77.625 cm.

8 0

3 years ago

What is the mass of an object whose momentum is 35kg-m/s ..when its velocity is 7m/s

MAXImum [283]

Answer:

5kg

Explanation:

p = mv

m = p/v

m = 35/7

m = 5kg

4 0

3 years ago

Read 2 more answers

A car enters the freeway with a speed of 6.4 m/s and accelerates uniformly for 3/2 km in 3.5 min. How fast (in m/s) is the car m

timama [110]

Answer:

7.9m/s

Explanation:

we need to convert the given values to metres and seconds

3/2km = 1500m and 3.5min = 210s

Using the first key equation of accelerated motion:

d = ((vi+vf)/2) x t

1500m = ((6.4+vf)/2) x 210 (plug in values)

3000m = (6.4 + vf) x 210 (get rid of the denominator by multiplying both sides by 2)

14.29 = 6.4 + vf (divide both sides to get rid of time)

vf = 7.885 m/s (subtract 6.4 from the right side to isolate vf)

2 significant digit answer is 7.9m/s

4 0

3 years ago