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Nuetrik [128]
2 years ago
11

Recall that impulse = momentum (FAt = Ap and that Ap is just mx v). How long (time) must a group of people pull with a force of

600N on a stalled 1500kg car to give it a velocity of 1.5m/s? Report your answer to the nearest hundredth (X.XX)​
Physics
1 answer:
elixir [45]2 years ago
6 0

The time taken for the group of people to pull the car, giving it a velocity of 1.5 m/s is 3.75 s

Momentum is simply defined as the product of mass and velocity i.e

Momentum = mass × velocity

To answer the question given, we'll begin by calculating the change in momentum. This can be obtained as follow:

Mass = 1500 Kg

Initial velocity (u) = 0 m/s

Final velocity (v) = 1.5 m/s

<h3>Change in momentum =? </h3>

Change in momentum = m(v – u)

Change in momentum = 1500 (1.5 – 0)

Change in momentum = 1500 × 1.5

<h3>Change in momentum = 2250 Kg•m/s</h3>

Finally, we shall determine the time

Change in momentum = 2250 Kg•m/s

Force (F) = 600 N

<h3>Time (t) =? </h3>

Impulse = Ft = change in momentum

FT = change in momentum

600 × t = 2250

Divide both side by 600

t = 2250 / 600

<h3>t = 3.75 s</h3>

Thus, the time required is 3.75 s

Learn more on momentum and impulse: brainly.com/question/14486244

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If speed = distance/time , then time = speed/distance.

So...

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I hope this was a helpful explanation, please reply if you have further questions about the problem.

Good luck!
5 0
2 years ago
A person notices a mild shock if the current along a path through the thumb and index finger exceeds 82 µA. Find the maximum all
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Answer:

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Explanation:

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Solution

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since acceleration and mass have inverse relation from the formula , the order of the acceleration will also be reverse.

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