Answer:
72
Explanation:
The displacement of an object can be found from the velocity of the object by integrating the expression for the velocity.
In this problem, the velocity of the sport car is given by the expression
In order to find the expression for the position of the car, we integrate this expression. We find:
where C is an arbitrary constant.
Here we want to find the displacement after 3 seconds. The position at t = 0 is
While the position after t = 3 s is
Therefore, the displacement of the car in 3 seconds is
Answer:
melting of rock deep underground.
Explanation:
The melting of rocks deep underground does not produce sedimentary rocks. Most igneous rocks are produced by this process.
When molten rocks underground called magma is solidified in the subsurface, it results into the formation of igneous bodies.
- Sedimentary rocks forms by the accumulation of sediments.
- Inside the basin where the sediments are deposited, they are compacted, cemented and lithified.
- Chemical and physical weathering of rocks produces sediments.
Speed of wave is given as
Wavelength of the wave is given as
now from the formula of wave time period we can say
so it will have time period of T = 4 s
One km^3 is 1,000,000,000 m^3=10^9 m^3 hence 3.73 10^8 km^3 is 3.73 10^17 m^3
One meter is 3.28084 feet hence 1 m^3 is (3.28084)^3 feet
Thus 3.73 10^8 km^3 is 3.73*35.315 10^17 = 132 cubic feet
Answer:
865.08 m
Explanation:
From the question given above, the following data were obtained:
Initial velocity (u) = 243 m/s
Height (h) of the cliff = 62 m
Horizontal distance (s) =?
Next, we shall determine the time taken for the cannon to get to the ground. This can be obtained as follow:
Height (h) of the cliff = 62 m
Acceleration due to gravity (g) = 9.8 m/s²
Time (t) =?
h = ½gt²
62 = ½ × 9.8 × t²
62 = 4.9 × t²
Divide both side by 4.9
t² = 62/4.9
Take the square root of both side.
t = √(62/4.9)
t = 3.56 s
Finally, we shall determine the horizontal distance travelled by the cannon ball as shown below:
Initial velocity (u) = 243 m/s
Time (t) = 3.56 s
Horizontal distance (s) =?
s = ut
s = 243 × 3.56 s
s = 865.08 m
Thus, the cannon ball will impact the ground 865.08 m from the base of the cliff.
